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ANEK [815]
2 years ago
5

What is the intersection of line CA a and line XA?

Mathematics
1 answer:
Oduvanchick [21]2 years ago
3 0

Answer:

point A is the intersection point between XA and AC

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Solve by factoring<br> 3v^2-10v+3=
jolli1 [7]

3v^2-10v+3=0\\\\\implies 3v^2 - 9v-v +3=0\\ \\\implies 3v(v-3)-(v-3)=0\\\\\implies (v-3)(3v-1)=0\\\\\implies v = 3,~~v=\dfrac 13

8 0
3 years ago
The distribution of blood cholesterol level in the
qaws [65]

Answer: A. Mean of sampling means =\mu=168\ Mg/dl

Standard deviation of sampling means =2.86\ mg/dl

B. The probability that your sample has mean less than  165 is 0.1492 .

Given : The distribution of blood cholesterol level in the

population of young men aged 20 to 34 years is close to normal with

mean \mu= 168 Mg/dl and standard deviation \sigma= 35 mg/dl.

Sample size : n= 150

Let \overline{x} sample mean values.

A. The mean and the  standard deviation of the distribution of the sampling means would be :

Mean of sampling means =\mu=168\ Mg/dl

Standard deviation of sampling means = \dfrac{\sigma}{\sqrt{n}}=\dfrac{35}{\sqrt{150}}

=\dfrac{35}{12.2474487}\\\\=2.85773803649\approx2.86\ mg/dl

The probability that your sample has mean less than  165 would be

P(\overline{x}

Hence , the probability that your sample has mean less than  165 is 0.1492 .

7 0
3 years ago
What is the net price of a dress marked $80 if it is reduced by 12%?show working please​
astraxan [27]

Answer: 9.6$

Step-by-step explanation:

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3 years ago
(1 point) Some shrubs have the useful ability to resprout from their roots after their tops are destroyed. Fire is a particular
ziro4ka [17]

Answer:

The answer is "0.45 \pm 0.18204"

Step-by-step explanation:

For the +4 sample proportion= \frac{(7+2)}{(16+4)} =  \frac{9}{20} = 0.45

Sample percentage measurements estimated stdev

= \sqrt{\frac{[(0.45)(1-0.45)]}{[(16+4)]}}\\\\ = \sqrt{\frac{[(0.45)(0.55)]}{[(20)]}}\\\\ = \sqrt{\frac{0.2475}{20}}\\\\= \sqrt{0.012375}\\\\=0.111

Calculating the critical z for a=0.1, two-tailed = 1.64

Calculating the confidence interval:

= 0.45 \pm 0.111 \times 1.64 \\\\= 0.45 \pm 0.18204

4 0
3 years ago
Use rounding or compatible numbers to estimate the difference 192-78
pogonyaev
The answer would be 110
5 0
4 years ago
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