Answer: A. Mean of sampling means 
Standard deviation of sampling means =
B. The probability that your sample has mean less than 165 is 0.1492 .
Given : The distribution of blood cholesterol level in the
population of young men aged 20 to 34 years is close to normal with
mean
Mg/dl and standard deviation
mg/dl.
Sample size : n= 150
Let
sample mean values.
A. The mean and the standard deviation of the distribution of the sampling means would be :
Mean of sampling means =
Standard deviation of sampling means = 

The probability that your sample has mean less than 165 would be

Hence , the probability that your sample has mean less than 165 is 0.1492 .
Answer: 9.6$
Step-by-step explanation:
Answer:
The answer is "
"
Step-by-step explanation:
For the +4 sample proportion
Sample percentage measurements estimated stdev
![= \sqrt{\frac{[(0.45)(1-0.45)]}{[(16+4)]}}\\\\ = \sqrt{\frac{[(0.45)(0.55)]}{[(20)]}}\\\\ = \sqrt{\frac{0.2475}{20}}\\\\= \sqrt{0.012375}\\\\=0.111](https://tex.z-dn.net/?f=%3D%20%5Csqrt%7B%5Cfrac%7B%5B%280.45%29%281-0.45%29%5D%7D%7B%5B%2816%2B4%29%5D%7D%7D%5C%5C%5C%5C%20%3D%20%5Csqrt%7B%5Cfrac%7B%5B%280.45%29%280.55%29%5D%7D%7B%5B%2820%29%5D%7D%7D%5C%5C%5C%5C%20%3D%20%5Csqrt%7B%5Cfrac%7B0.2475%7D%7B20%7D%7D%5C%5C%5C%5C%3D%20%5Csqrt%7B0.012375%7D%5C%5C%5C%5C%3D0.111)
Calculating the critical z for a=0.1, two-tailed = 1.64
Calculating the confidence interval:
