Hello,
the answer is fibrous roots
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propeller injury
Answer:
Energy added to cold water, E1
E1 = m•Cp•ΔT = 6 x 4.187x(42-20) = 6x4.187x22
Energy lost by hot water, E2:
E2 = X(CpΔT) = X x 4.187 x (75-42) =X x 4.187 x 33
So, since E1 = E2
6x4.187x22 = X x 4.187 x 33
X = 6x22/33 = 4.0kg
So the mass of the hot water added to the 6kg of cold water is 4.0kg
