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Nataliya [291]
2 years ago
14

What is the measurement of m? 24 6

Mathematics
1 answer:
BlackZzzverrR [31]2 years ago
4 0

The value of n is 12. and m is 6root5

We have given the diagram,

The measurement of m,

n = 12

According to the altitude theorem

<h3>What is the altitude theorem?</h3>

The right triangle altitude theorem or geometric mean theorem is a result in elementary geometry that describes a relation between the altitude on the hypotenuse in a right triangle and the two-line segments it creates on the hypotenuse.

24/n = n/6

The Cross multiply

24 * 6 = n²

144 = n²

n² = 144

n = √144

n = 12

m^2=6^2+n^2

m^2=6^2+12^2\\m^2=36+144\\m^2=180

m=\sqrt{180} \\m=2\cdot \:3\sqrt{5}\\m=6\sqrt{5}

Hence the value of n is 12.

To learn more about the measurement visit:

brainly.com/question/25716982

#SPJ1

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Answer:

A= 3215.36 in²

C= 100.48 in

Step-by-step explanation:

A= πr²

A=3.14(<u>32²</u>)

A= <u>3.14(1024)</u>

A= 3215.36 in²

C= πd

C= <u>3.14(32)</u>

C= 100.48 in

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Answer:

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Step-by-step explanation:

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Answer:

About 463%

Step-by-step explanation:

600*12= 7200

7200*30= 216000

1,000,000/ 216000 = about 4.63

Check:

4.63*216000= 1,000,080

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Jefferson works part time and earns 1,520 in four weeks . How much does he earn each week ?
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Suppose that a jewelry store tracked the amount of emeralds they sold each week to more accurately estimate how many emeralds to
RUDIKE [14]

Answer:

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75

And for the margin of error we have the following estimation:

ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75

And for the margin of error we have the following estimation:

ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62

5 0
3 years ago
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