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Dmitrij [34]
2 years ago
15

Help me please I need this for tomorrow please please

Mathematics
2 answers:
Andrews [41]2 years ago
8 0
Need a better picture if u post it again soon I’ll see it and I’ll tell u
GrogVix [38]2 years ago
3 0
Answer is question B make brainliest thanks
You might be interested in
Which values of k are solutions to the inequality |-k-2|&lt;18? Check all that apply<br> -40
LenaWriter [7]

Answer:

any number except -20

Step-by-step explanation:

|-k-2|

-k-2                              -k-2>18

-k                               -k>18+2

-k                                      -k>20

Multiply by -1 to make the k positive. This will alter all the terms which means 20 will become negative. NOTE: When multiplying or dividing by negative numbers, the inequaliy sign flips.

k>-20                                           k

k must be either greater than -20 but not including it or fewer than -20 but not including it; therefore, any number between negative infinity and -21 and -19 and postive infinity

6 0
3 years ago
Read 2 more answers
Which of the following expressions is equal to -3x^2-27?
Iteru [2.4K]

Answer:

6

\sqrt{2}

3 0
3 years ago
What is the solution set for the open sentence with the given replacement set y2 -3=y+ [0,1,3,4]
stich3 [128]
It is three cuz when replace with three it is all equal:
3(2)-3=3
6-3=3
3=3
please rate as brainliest and hope this helps :)
7 0
3 years ago
How do i solve this?
shusha [124]

Answer:

Step-by-step explanation:

You can use Pythagoras Theorem,

8^{2} + y^{2}  = (8\sqrt{6} )^{2} \\      y^{2}        = (8\sqrt{6} )^{2} - 8^{2} \\y^{2} = 384 - 64\\y^{2} = 320\\y  = \sqrt{320}

∴ y = 8\sqrt{5}

Hope that helps!!

Please mark as Brainliest!!

7 0
3 years ago
Given the right triangle below what is x?
lions [1.4K]

Answer:

B 10.8 or

A 9.2 depending on what side of the triangle is "x".

Step-by-step explanation:

we cannot see the triangle and which side is which. you forgot to show us the picture (or describe it in more detail).

but I assume that "x" would be the Hypotenuse (the baseline of the right triangle, the side opposite of the 90 degree angle).

then by using Pythagoras

c² = a² + b²

=>

x² = 10² + 4² = 116

x = sqrt(116) = 10.8

but if x is any of the other sides (and not the Hypotenuse), then you need to adapt the calculation.

for example, if the Hypotenuse is the side with 10, then Pythagoras' formula would look like this

10² = x² + 4²

x² = 10² - 4² = 84

x = sqrt(84) = 9.2 (and answer A would be correct).

or if the Hypotenuse is the side with 4, then

4² = x² + 10²

x² = 4² - 10² = -84

x = sqrt(-84)

and that did not make any sense for real distances. so, this configuration is actually impossible for a right triangle.

5 0
3 years ago
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