Question

Find the zero of the given polynomial :01" id="TexFormula1" title="p(x) = {x}^{2} + 1" alt="p(x) = {x}^{2} + 1" align="absmiddle" class="latex-formula">​

Answer 1

Answer:

x = i, -i

Explanation:

p(x) = x² + 1

To set a polynomial to zero, p(x) = 0.

⇒ x² + 1 = 0

relocate variable

⇒ x² = -1

square root both sides

⇒ x = ±√-1

breakdown

⇒ x = √-1, -√-1

simplify if x = √-a then √a i

⇒ x = i, -i

Answer 2

Answer:

+i , -i

Step-by-step explanation:

Zero of the polynomial:

   p(x) =0

x² + 1 = 0

      x² = -1

     Take square root both sides,

      $\sf x = \sqrt{-1}\\\\x =\sqrt{i^2}$

     x = ± i

Zeros of the polynomial:

   x = +i , -i