Find the zero of the given polynomial :
01" id="TexFormula1" title="p(x) = {x}^{2} + 1" alt="p(x) = {x}^{2} + 1" align="absmiddle" class="latex-formula">
2 answers:
Answer:
x = i, -i
Explanation:
p(x) = x² + 1
To set a polynomial to zero, p(x) = 0.
⇒ x² + 1 = 0
relocate variable
⇒ x² = -1
square root both sides
⇒ x = ±√-1
breakdown
⇒ x = √-1, -√-1
simplify if x = √-a then √a i
⇒ x = i, -i
Answer:
+i , -i
Step-by-step explanation:
<h3>Zero of the polynomial:</h3>
p(x) =0
x² + 1 = 0
x² = -1
Take square root both sides,
x = ± i
Zeros of the polynomial:
x = +i , -i
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