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weeeeeb [17]
2 years ago
15

How do I Expand (2x − 1)^6

Mathematics
1 answer:
Veronika [31]2 years ago
6 0

Answer:

well if u do this

(2x-1)(2x-1)(2x-1)(2x-1)(2x-1)(2x-1)

it would be the expanded form for (2x-1)^6

Step-by-step explanation:

i um learned it before so...

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Please help me urgent!!
arsen [322]
<h3>Hey! </h3>

\sf \longmapsto S_{ 20} =  \dfrac{n}{2}  \times 2a + (n - 1)d \\  \\ \sf\longmapsto S_{20}= \dfrac{20}{2}  \times 2(2) + (20 - 1)6 \\  \\ \sf\longmapsto S_{20}  = 10 \{ 4 + 114 \} \\ \\ \sf \longmapsto \boxed{\bf{S_{20} = 1180}}

Hope it helps :)

8 0
3 years ago
What is the solution to to the equation x − 2/5 = −1?
ZanzabumX [31]

Answer:

  • x = -0.6

Step-by-step Solution:

<u>Isolate the variable x to get the answer.</u>

  • x − 2/5 = −1
  • => x = -1 + 2/5
  • => x = -1 + 0.4
  • => x = -0.6

Hence, the value of x is -0.6.

6 0
2 years ago
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Please answer correctly! I will mark you Brainliest! The pictures go together!
Brums [2.3K]

Answer:

81 feet squared

Step-by-step explanation:

9^2 = 81

3 0
3 years ago
You want to invest $400 in stock ORS. How many more shares of QRS will
eimsori [14]

Answer:

1 share APEX

Step-by-step explanation:

5 0
3 years ago
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The perimeter of a triangle is 300 m . If its sides are in the ratio 3:5:7. Find the area of the triangle.
nalin [4]

Answer:

<em><u>If </u></em><em><u>the </u></em><em><u>perimeter</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>3</u></em><em><u>0</u></em><em><u>0</u></em><em><u>m</u></em>

<em><u>let </u></em><em><u>the </u></em><em><u>ratio </u></em><em><u>be </u></em><em><u>in </u></em><em><u> </u></em><em><u>x </u></em>

<em><u>a/</u></em><em><u>q</u></em><em><u>. </u></em>

<em><u>3</u></em><em><u>x</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>5</u></em><em><u>x</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>7</u></em><em><u>x</u></em><em><u>. </u></em><em><u>=</u></em><em><u> </u></em><em><u>3</u></em><em><u>0</u></em><em><u>0</u></em><em><u>m</u></em>

<em><u>1</u></em><em><u>5</u></em><em><u>x</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>3</u></em><em><u>0</u></em><em><u>0</u></em>

<em><u>x </u></em><em><u>=</u></em><em><u> </u></em><em><u>3</u></em><em><u>0</u></em><em><u>0</u></em><em><u>/</u></em><em><u>1</u></em><em><u>5</u></em>

<em><u>x </u></em><em><u>=</u></em><em><u> </u></em><em><u>2</u></em><em><u>0</u></em>

<em><u>hence</u></em><em><u> </u></em><em><u>angles </u></em><em><u>are </u></em>

<em><u>6</u></em><em><u>0</u></em><em><u> </u></em><em><u>,</u></em><em><u> </u></em><em><u>1</u></em><em><u>0</u></em><em><u>0</u></em><em><u> </u></em><em><u>and </u></em><em><u>1</u></em><em><u>4</u></em><em><u>0</u></em>

<em><u>hope</u></em><em><u> it</u></em><em><u> helps</u></em>

6 0
3 years ago
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