Hi there! :)
Solve for j(h(x)):
h(x) = x² + 4
j(x) = 4x - 1
Substitute in h(x) into "x":
j(h(x)) = 4(x² + 4) - 1
j(h(x)) = 4x² + 16 - 1
j(h(x)) = 4x² + 15
Solve at x = 2:
4(2)² + 15 = 4(4) + 15 = 31.
<span>When two tangent lines intersect, they form an angle that equals
one half (larger intercepted arc minus the smaller </span><span>intercepted arc)
So, angle CLA = (1/2) (200 -160)
</span><span>Angle CLA = (1/2) (40)
</span><span>Angle CLA = 20 degrees
Source:
http://www.1728.org/circangl.htm
</span>
Answer:
100
Step-by-step explanation:
20/2= 10 and 10 squared is 100 but you have to move the -6 to the opposite side
Answer:
If 12,000 are put at an account with 2.5% compound interest in 15 years your total would be $17,379.58
Answer:
ntersecting lines DA and CE.
To find:
Each pair of adjacent angles and vertical angles.
Solution:
Adjacent angles are in the same straight line.
Pair of adjacent angles:
(1) ∠EBD and ∠DBC
(2) ∠DBC and ∠CBA
(3) ∠CBA and ∠ABE
(4) ∠ABE and ∠EBD
Vertical angles are opposite angles in the same vertex.
Pair of vertical angles:
(1) ∠EBD and ∠CBA
(2) ∠DBC and ∠EBA
