PLEASE help will mark brainliest algebra 2 . ... show your work
1 answer:
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Let's turn this into a fraction using the given information we already have.
We want the denominator, or the bottom part of the fraction, to be 1 in order for us to have a unit rate.
This fraction can be simplified if we divide both the numerator and denominator by 3.
Numerator: 18/3 = 6
Denominator: 3/3 = 1
Now we have
Any number divided by 1 is equal to that number.
Thus, your unit rate is 6 miles per hour.
Have an awesome day! :)
~AgentCozmo4, Junior Moderator
We want the denominator, or the bottom part of the fraction, to be 1 in order for us to have a unit rate.
This fraction can be simplified if we divide both the numerator and denominator by 3.
Numerator: 18/3 = 6
Denominator: 3/3 = 1
Now we have
Any number divided by 1 is equal to that number.
Thus, your unit rate is 6 miles per hour.
Have an awesome day! :)
~AgentCozmo4, Junior Moderator
Answer:
a) 0.0498
b) 0.1489
c) 0.1818
Step-by-step explanation:
Given:
Number of telephones = 6+6+6= 18
6 cellular, 6 cordless, and 6 corded.
a) Probability that all the cordless phones are among the first twelve to be serviced:
12 are selected from 18 telephones, possible number of ways of selection = ¹⁸C₁₂
Then 6 cordless telephones are serviced, the remaining telephones are: 12 - 6 = 6.
The possible ways of selecting thr remaining 6 telephones = ¹²C₆
Probability of servicing all cordless phones among the first twelve:
= (⁶C₆) (⁶C₁₂) / (¹⁸C₁₂)
b) Probability that after servicing twelve of these phones, phones of only two of the three types remain to be serviced:
Here,
One type must be serviced first
The 6 remaining to be serviced can be a combination of the remaining two types.
Since there a 3 ways to select one type to be serviced, the probability will be:
= 3 [(⁶C₁)(⁶C₅) + (⁶C₂)(⁶C₄) + (⁶C₃)(⁶C₃) + (⁶C₄)(⁶C₂) + (⁶C₅)(⁶C₁)] / ¹⁸C₁₂
c) probability that two phones of each type are among the first six:
(⁶C₂)³/¹⁸C₆