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zvonat [6]
2 years ago
13

Find the least number that must be subtracted from 21 2o show the result is a perfect square​

Mathematics
1 answer:
ivanzaharov [21]2 years ago
5 0

Answer:

5

Step-by-step explanation:

2 × 2 = 4

3× 3 = 9

4 × 4 =16

5 × 5 =25

16 is the only number and closest number to 21 to subtract from

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If a solid has faces that consist of 2 equilateral triangles and 3 congruent rectangles, what type of solid is it?
svlad2 [7]
A right triangular prism is a solid that has faces that consist of 2 equilateral triangles and 3 congruent rectangles. It is also described to have two parallel faces and 3 other faces that belong to the same place (and are not parallel to the parallel pair of faces).
5 0
3 years ago
A circle with a radius of 5 is inscribed in a equilateral triangle. What is the area of the triangle's area minus the circle's a
Aleonysh [2.5K]
First off, the area of the circle would be 78.54

Now, you would do (area of the triangle)--- AT-78.54=answer

I don't know how to find the area of the triangle with just the circle's radius, so this is all I can do. I'm sorry!
4 0
4 years ago
Solve similar triangles (advanced)<br> Solve for x<br> x=?
lesya692 [45]

Answer:

x = 1.2

Step-by-step explanation:

AD/AB = DE/BC (Similarity Theorem)

AD = 6 + 4 = 10

AB = 6

DE = 2

BC = x

Plug in the values

10/6 = 2/x

Cross multiply

10*x = 2*6

10x = 12

Divide both sides by 10

x = 12/10

x = 1.2

8 0
3 years ago
Which equation describes the line graphed above? JUST NEED ANSWER NO NEED FOR EXPLANATION
Zolol [24]

Answer:

B.

Step-by-step explanation:

We can use a graphing calc to determine which line is the correct one.

4 0
3 years ago
Read 2 more answers
3^x= 3*2^x solve this equation​
kompoz [17]

In the equation

3^x = 3\cdot 2^x

divide both sides by 2^x to get

\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3

Take the base-3/2 logarithm of both sides:

\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}

Alternatively, you can divide both sides by 3^x:

\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13

Then take the base-2/3 logarith of both sides to get

\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}

(Both answers are equivalent)

8 0
3 years ago
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