Answer:
1. create the first array A
2. create the second array A1, the same length as array A.
3. create a loop to iterate over both arrays for a number of times specific to the length of the arrays, with a condition to get and pop only the minimum value of which arrays for every loop.
4. save both items to "a" for minimum value A and "b" for minimum value A1.
5. call a function to push the "a" variable value to A1 and "b" variable value to the array A.
Explanation:
This code would interchange the values of both arrays, the best-case scenario for the code is O( n ) where n is the number of items in both arrays and worst is the best-case multiplied by the number of time to compare all the items with the minimum value.
Answer:
i play rblx
Explanation:
queenloveadriana (main acc)
AdiosLoca (alt)
Azazel_Iblis (the acc I'll use for my YT channel)
I also play Fn, CofD, Destiny, 2k, Mortal Combat, but my PS4 broke and I'm waiting to get my PS5 that I ordered
Answer:
True.
Explanation:
"1" to "M" or 1 to many is a type of relationship between tables in a relational database. It means that against 1 record in a table, there can be 0 to many rows in the other table. Not that the many or child table doesn't need to have any record against the 1 or parent row, so the many side is optional.
Example can be a Customer and Order relationship. Where Customer is the parent table and Order is the child table. "A customer can have 0 to many orders".
Know what your trying to say her input pound 45-94