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____ [38]
1 year ago
11

Or dylan, an nfl running back, rushed for an average of 88 yards per game this season, which is 20% lower than his average was l

ast season. what was his average then?
Mathematics
1 answer:
faltersainse [42]1 year ago
3 0
His previous average was 96 yards per game
You might be interested in
Sara collected $135 in donations for the hospital. This represents 5 percent of total collected. How much did the class collect
PIT_PIT [208]

Answer:

$2,700

Step-by-step explanation:

Find the total donation amount by dividing 135 by 0.05:

135/0.05

= 2700

So, the class collected $2,700 in all

5 0
3 years ago
Read 2 more answers
Prof Liu gave the same quiz to the students in her morning class and in her afternoon class. the average score for the two class
yaroslaw [1]

Answer:

Step-by-step explanation:

Given that Prof  Liu gave the same quiz to the students in her morning class and in her afternoon class. the average score for the two classes combined was 84.

(1) The average score for the students in the morning class was 80

(2) the average score for the students in the afternoon class was 86

Let m be the no of students in I class and n in II class

Total of I class = 80m and

Total of II class = 86n

Total of both classes = 80m +86n

Average =\frac{80m+86n}{m+n} = 84

m cannot be equal to n because in that case average would have been 83

If m >n, then say n =m+a

then average = \frac{80m+86m+86a}{2m+a} =84

Because 86 is more times added, average score would decrease hence we would not get 84.

So I class is getting less score of 80 to get a score average of more than 83 (the average) the class II should have more students.

4 0
3 years ago
Determine the zero of F(x)=x^2+3x-5
IgorLugansk [536]

Answer:

The answer to your question is:

Step-by-step explanation:

                                             x² + 3x - 5

                                    x² + 3x + (3/2)² = 5 + (3/2)²

                                         (x + 3/2)² = 5 + 9/4

                                         (x + 3/2)² = (20 + 9) /4

                                          (x + 3/2)² = 29/4

                                          x + 3/2 = ±√29 / 2

                                     

x 1 = -3/2 + √29/2                               x2 = -3/2 - √29/2

x1 = 1.19                                                x2 = -4.19

3 0
3 years ago
Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive
NeX [460]

Answer:

(a) 0.343

(b) 0.657

(c) 0.189

(d) 0.216

(e) 0.353

Step-by-step explanation:

Let P(a vehicle passing the test) = p

                        p = \frac{70}{100} = 0.7  

Let P(a vehicle not passing the test) = q

                         q = 1 - p

                         q = 1 - 0.7 = 0.3

(a) P(all of the next three vehicles inspected pass) = P(ppp)

                           = 0.7 × 0.7 × 0.7

                           = 0.343

(b) P(at least one of the next three inspected fails) = P(qpp or qqp or pqp or pqq or ppq or qpq or qqq)

      = (0.3 × 0.7 × 0.7) + (0.3 × 0.3 × 0.7) + (0.7 × 0.3 × 0.7) + (0.7 × 0.3 × 0.3) + (0.7 × 0.7 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.3)

      = 0.147 + 0.063 + 0.147 + 0.063 + 0.147 + 0.063 + 0.027

      = 0.657

(c) P(exactly one of the next three inspected passes) = P(pqq or qpq or qqp)

                 =  (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7)

                 = 0.063 + 0.063 + 0.063

                 = 0.189

(d) P(at most one of the next three vehicles inspected passes) = P(pqq or qpq or qqp or qqq)

                 =  (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7) + (0.3 × 0.3 × 0.3)

                 = 0.063 + 0.063 + 0.063 + 0.027

                 = 0.216

(e) Given that at least one of the next 3 vehicles passes inspection, what is the probability that all 3 pass (a conditional probability)?

P(at least one of the next three vehicles inspected passes) = P(ppp or ppq or pqp or qpp or pqq or qpq or qqp)

=  (0.7 × 0.7 × 0.7) + (0.7 × 0.7 × 0.3) + (0.7 × 0.3 × 0.7) + (0.3 × 0.7 × 0.7) + (0.7 × 0.3 × 0.3) + (0.3 × 0.7 × 0.3) + (0.3 × 0.3 × 0.7)

= 0.343 + 0.147 + 0.147 + 0.147 + 0.063 + 0.063 + 0.063

                  = 0.973  

With the condition that at least one of the next 3 vehicles passes inspection, the probability that all 3 pass is,

                         = \frac{P(all\ of\ the\ next\ three\ vehicles\ inspected\ pass)}{P(at\ least\ one\ of\ the\ next\ three\ vehicles\ inspected\ passes)}

                         = \frac{0.343}{0.973}

                         = 0.353

3 0
3 years ago
Read 2 more answers
6−3(5x+2)−10x please explain the steps on how to simplify this polynomials.
kati45 [8]

Step-by-step explanation:

6-15x-6-10x

put the like terms together and it's now -15x-10x+6-6

-25+6-6

=-25

6 0
1 year ago
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