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Flura [38]
2 years ago
13

The quotient of a number p and 38

Mathematics
1 answer:
kodGreya [7K]2 years ago
3 0

Answer:

\frac{p}{38}

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Margaret [11]
The greatest common factor is 6

36: 1, 2, 3, 4, 6, 9, 12, 18, 36
42: 1, 2, 3, 6, 7, 14, 21, 42


Hope this helps : )
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I don’t know what to do
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20% of 15 is 12$, and tax is 5% so it comes out to 12.60$
The answer is B
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An object is launched from a launching pad 144 ft. above the ground at a velocity of 128ft/sec. what is the maximum height reach
ollegr [7]

Answer:

18) a. h(x) = -16x² + vx + h(0) ⇒ h(x) = -16x² + 128x + 144

b. The maximum height = 400 feet

c. Attached graph

19) The rocket will reach the maximum height after 4 seconds

20) The rocket hits the ground after 9 seconds

Step-by-step explanation:

* Lets study the rule of motion for an object with constant acceleration

# The distance S = ut ± 1/2 at², where u is the initial velocity, t is the time

  and a is the acceleration of gravity

# The vertical distances h in x second is h(x) - h(0), where h(0)

   is the initial height of the object above the ground

∵ h(x) = vx + 1/2 ax², where h is the vrtical distance, v is the initial

  velocity, a is the acceleration of gravity (32 feet/second²) and x

  is the time

18)a.

∵ The value of a = -32 ft/sec² ⇒ negative because the direction

   of the motion

  is upward

∴ h(x) - h(0) = vx - (1/2)(32)(x²) ⇒ (1/2)(32) = 16

∴ h(x) = vx - 16x² + h(0)

∴ h(x) = -16x² + vx + h(0) ⇒ proved

* Find the height of the object after x seconds from the ground

∵ h(0) = 144 and v = 128 ft/sec

∴ h(x) = -16x² + 128x + 144

b.

* At the maximum height h'(x) = 0

∵ h'(x) = -32x + 128

∴ -32x + 128 = 0 ⇒ subtract 128 from both sides

∴ -32x = -128 ⇒ ÷ -32

∴ x = 4 seconds

- The time for the maximum height = 4 seconds

- Substitute this value of x in the equation of h(x)

∴ The maximum height = -16(4)² + 128(4) + 144 = 400 feet

c. Attached graph

19)

- The object will reach the maximum height after 4 seconds

20)

- When the rocket hits the ground h(x) = 0

∵ h(x) = -16x² + 128x + 144

∴ 0 = -16x² + 128x + 144 ⇒ divide the two sides by -16

∴ x² - 8x - 9 = 0 ⇒ use the factorization to find the value of x

∵ x² - 8x - 9 = 0

∴ (x - 9)( x + 1) = 0

∴ x - 9 = 0 OR x + 1 = 0

∴ x = 9 OR x = -1

- We will rejected -1 because there is no -ve value for the time

* The time for the object to hit the ground is 9 seconds

8 0
3 years ago
The function. In the graph is f(x) =
Tanya [424]

Answer:

x^3-2x^2-5x+6

Step-by-step explanation:

We have been given a graph of the function f(x).

Now we need to use that graph to find the equation of the graph and match with the correct choice from the give choices:

x^4-2x^2+5x+6

x^3-2x^2-5x+6

x^3-2x^2+5x+6

-x^4-2x^2+5x+6

We see that graph has end points in opposite direction then the degree of polynomial must be ODD.

Available degrees are 3 and 4. Degree 3 is odd so it is choice B or C.

Only x^3-2x^2-5x+6 satisfies the given points from graph.

Hence correct choice is x^3-2x^2-5x+6.

4 0
3 years ago
A telephone booth that is 8 ft tall casts a shadow that is 4ft long. Find the height of a lawn ornanment that casts a 2 ft shado
sukhopar [10]
8 ft /4 ft of shadow=x / 2 ft of shadow
x=(8 ft * 2 ft of shadow) / 4 ft of shadow=4 ft

height of a lawn ornament=4 ft
5 0
3 years ago
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