Answer:
<h2>
<u>Option</u><u> </u><u>B</u></h2>
<u>it</u><u> </u><u>represents</u><u> </u><u>the</u><u> </u><u>product</u><u> of</u><u> </u><u>two</u><u> </u><u>irrational</u><u> </u><u>numbers </u><u>and</u><u> </u><u>is</u><u> </u><u>equivalent</u><u> </u><u>to</u><u> </u><u>an</u><u> </u><u>irrational</u><u> </u><u>number.</u>
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Answer:
1. sinα = +2√5/5 2. cosα = +√5/5 3. cotα = +1/2 4. secα = +√5 5. cosecα = +√5/2.
Step-by-step explanation:
1. Since tan(α) = 2 and 1 + cot²α = cosec²α
1 + 1/tan²α = 1/sin²α
1 + 1/2² = 1/sin²α
1 + 1/4 = 1/sin²α
5/4 = 1/sin²α
sinα = ±√(4/5)
sinα = ±2/√5
sinα = ±2√5/5
Since 0<α<π/2, sinα = +2√5/5
2. sin²α + cos²α = 1
(2/√5)² + cos²α = 1
4/5 + cos²α = 1
cos²α = 1 - 4/5
cos²α = 1/5
cosα = ±1/√5
cosα = ±√5/5
Since 0<α<π/2, cosα = +√5/5
3. cotα = 1/tanα = 1/2
Since 0<α<π/2, cotα = +1/2
4. secα = 1/cosα = 1/±1/√5 = ±√5
Since 0<α<π/2, secα = +√5
5. cosecα = 1/sinα = 1/±2/√5 = ±√5/2
Since 0<α<π/2, cosecα = +√5/2
<span>|x| is x if x>0
|x| is -x if x<0
|x| is 0 if x=0
so
(|x|)'=1 when x>0
so
(|x|)'=-1 when x<0
</span><span> (|2x-4|)'=2 when x>2
and
(|2x-4|)'=-2 when x<2
</span>
<span>Therefore the left derivative doesn't equal the right derivative as x approaches 2.</span>
Answer: 6
Step-by-step explanation:
3x = 18
Divide 18 by 3
x = 6