Answer:
y = -2x + 7 is the equation if that's what you are asking for.
Find the locus of a point P such that its ordinate is equal to the abscissa. Hence required equation of the locus of point P is y = 5x + 9. Hence required equation of the locus of point P is x = 2y + 3.
Answer:
are zeroes of given quadratic equation.
Step-by-step explanation:
We have been a quadratic equation:
We need to find the zeroes of quadratic equation
We have a formula to find zeroes of a quadratic equation:
General form of quadratic equation is 
On comparing general equation with b given equation we get
a=2,b=-10,c=-3
On substituting the values in formula we get
Now substituting D in 
we get
Therefore,
Answer:
x = -3/2
x = -1/2
Step-by-step explanation:
4x^2 + 8x + 3
4x^2 + 2x + 6x + 3
2x(2x+1) + 3(2x+1)
(2x + 3) (2x + 1)
x = -3/2
x = -1/2
Answer:
I believe that the third answer is correct..... but I'm not positive.
Step-by-step explanation:
if you get the third side of the triangle to be 71 then it would go first. Then it would go to 45-55. And lastly to 71-45
