Question

Point P is located at (−2, 7), and point R is located at (1, 0). Find the y value for the point Q that is located two thirds the distance from point P to point R.
4.9
4.7
2.5
2.3

Answer 1

Answer:

4.7

Explanation:

A point is positioned at minus two, seven. At one, zero, you'll find point R. Determine the value of Y. Regarding point Q. That is 2/3 of the distance between points P. So, negative two becomes positive seven. So, we have minus twenty-seven and 1 common zero. So, if we place a line between these, we must calculate the distance. First, you should be aware that you may achieve this using the distance formula. I prefer to conceive of it as the Pythagorean Theorem. So, the distance is 3^2 and 7^2, which is D^2. So, 9+49=58. And, we'll take the square root of it. As a result, the square root of 58=D. And, you want to be 2/3 the distance between points P and B. So, divide this by 2/3. So, this is close to 5.1. But, you want to get the Y value; found the distance, 2/3 of the way. When the distance is 5.1 instead of round 7.6, we've arrived at point P. We want to be 5. 1 yard away on this line. This is point P and we want to be at point Q. Since it'll have the same slope. As a result, the slope will be 7/3. So, it'll be proportionate 7. Since the square root of fifty-eight is too large. Route 58/3 is the destination. The square root of 258 is canceled. Such that 7=3y/2. 7x2=14/3=4.7. It's by locating comparable figures.