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1 year ago

PLS ANSWER THESE TWO QUESTIONS EXPLANATION IS NOT NEEDED MAKE SURE IT IS CORRECT

Mathematics

1 answer:

laila [671]1 year ago

6 0

The answers to the following word problems are given below:

(C). $1\frac{1}{2}$
(C). 0

<h3>Meaning of word problem</h3>

A Word problem can be defined as a mathematical problem that is given in a sentence format.

A word problem needs the student to decipher it and then translate it to a normal arithmetic problem.

In conclusion, The answers to the word problems are given

Learn more about word problems: brainly.com/question/13818690

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A study of a population of 3600 dogs found that 6 out of every 90 dogs have brown fur. Based on the results of this study, how m

nika2105 [10]

3600/90= 40 x 6 =240
3600 - 240 = 3360
3360 dogs in the population DO NOT have brown fur.

4 0

2 years ago

Solving Exponential and Logarithmic Equations In Exercise, solve for x.<br> In 2x - In(3x - 1) = 0

LenKa [72]

Answer:

$\frac{-1}{3x^2-x}$

Step-by-step explanation:

If f(x) is in th form of f(x)=g(x)-h(x) then f'(x)=g'(x) - h'(x)
When f(x)=z(g(x)) then f'(x)= z'(g(x))g'(x) (called as chain rule)

<u>using these information</u>:

g(x)=ln2x then g'(x)= $\frac{(2x)'}{2x} =\frac{2}{2x}=\frac{1}{x}$

h(x)=In(3x - 1) then h'(x)= $\frac{(3x-1)'}{3x-1} =\frac{3}{3x-1}f'(x)=g'(x) - h'(x) =[tex]\frac{1}{x} - \frac{3}{3x-1} =\frac{-1}{3x^2-x}$

7 0

3 years ago

7) 6x + 16 + = 2x + 28

Ede4ka [16]

Answer: the answer to number seven is x=3

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

How many terms dose 4x + 8y -1

solniwko [45]

3 terms 4x,8y and -1

3 0

2 years ago

Read 2 more answers

Find the distance between the pair of points.

SVEN [57.7K]

Answer:

Distance is $\sqrt{290}$ units

Step-by-step explanation:

Use the distance formula which is $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ where $d$ is the distance between points $(x_1,y_1)$ and $(x_2,y_2)$

We are given that $(x_1,y_1)$ is $(-6,-23)$ and $(x_2,y_2)$ is $(-23,-24)$ , therefore the distance between the two points is:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$d=\sqrt{(-23-(-6))^2+(-24-(-23))^2}$

$d=\sqrt{(-23+6))^2+(-24+23))^2}$

$d=\sqrt{(-17)^2+(-1)^2}$

$d=\sqrt{289+1}$

$d=\sqrt{290}$

Therefore, the distance between $(-6,-23)$ and $(-23,-24)$ is $\sqrt{290}$ units.

3 0

2 years ago