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OleMash [197]
2 years ago
6

Which of the following values can be found by using the formula √1+cos^2 0?

Mathematics
1 answer:
Sati [7]2 years ago
5 0

Let's check

Remove root over and simplify 1+cot²Ø

  • 1+cos²theta/sin²theta
  • sin²Ø+cos²Ø/sin²Ø
  • 1/sin²Ø
  • cosec²Ø

Putting root over

  • cscØ

Sin can be found also along with csc

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Solve the triangle using the law of cosines
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Answer:

wich one

Step-by-step explanation:

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Simplify this question m=12
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12x12=144
3x144=432
The answer is 432.
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IT IS FOR 100 POINTS
strojnjashka [21]

Answer:

See below

Step-by-step explanation:

I think it’s four less than the quotient of a number cubed and seven, increased by three

I hope you get this right!

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3 years ago
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Find the value of (+328.62) – (+98.6). A. 230.02 B. 427.22 C. –427.22 D. –230.02
Jet001 [13]

Answer:

Option A - (+328.62)-(+98.6)=230.02

Step-by-step explanation:

We have given the expression (+328.62)-(+98.6)

We have to find the value of the expression ?

Solution :

Step 1 - Write the expression

=(+328.62)-(+98.6)

Step 2 - Applying symbol rule i.e. multiplication of positive into negative is always negative, (-)(+)=(-)

=328.62-98.6

Step 3 - Solve

=230.02

Therefore, The value of the expression is (+328.62)-(+98.6)=230.02

So, Option A is correct.

7 0
3 years ago
In 4 ​minutes, a conveyor belt moves 800 pounds of recyclable aluminum from the delivery truck to a storage area. A smaller belt
kkurt [141]

Answer:

It takes 2 minutes 4 seconds to move the cans to storage area if both the belts are used.

Step-by-step explanation:

Given - In 4 ​minutes, a conveyor belt moves 800 pounds of recyclable

            aluminum from the delivery truck to a storage area. A smaller belt

            moves the same quantity of cans the same distance in 6 minutes.

To find - If both belts are​ used, find how long it takes to move the cans

              to the storage area.

Proof -

Given that,

Larger belt take 4 minutes to transfer the aluminium from delivery truck to storage area.

⇒ Time taken by Larger belt = 4 min/ shifting

Also,

Smaller belt take 6 minutes to transfer the aluminium from delivery truck to storage area.

⇒ Time taken by Smaller belt = 6 min/ shifting

Now,

As we know that Time is inversely proportional to time, so

Rate of Larger Belt = \frac{1}{4} shifting/min

Rate of Smaller Belt = \frac{1}{6} shifting/min

Now,

Let us assume that , if both belts used then,

Total time taken = x min/shifting

Then, Rate = \frac{1}{x} shifting/min

Now,

\frac{1}{4}  + \frac{1}{6}  = \frac{1}{x}

⇒\frac{6 + 4}{24} = \frac{1}{x}

⇒\frac{10}{24} = \frac{1}{x}

⇒10x = 24

⇒x = \frac{24}{10} = 2.4 minutes

∴ we get

It takes 2 minutes 4 seconds to move the cans to storage area if both the belts are used.

3 0
3 years ago
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