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melamori03 [73]
2 years ago
5

At a hockey game, a vender sold a combined total of 235 sodas and hot dogs. The number of hot dogs sold was 59 less than the num

ber of sodas sold. Find the number of sodas sold and the number of hot dogs sold.
Mathematics
1 answer:
Neko [114]2 years ago
5 0

Answer:

  • 147 sodas
  • 88 hot dogs

Step-by-step explanation:

This problem is similar to many others in which the sum of two quantities and their difference are given. The solution can be found easily when the equations for the relations are written in standard form.

<h3>Setup</h3>

Let s and h represent numbers of sodas and hot dogs sold, respectively. The given relations are ...

  • s +h = 235 . . . . . combined total
  • s -h = 59 . . . . . . difference in the quantities

<h3>Solution</h3>

Adding the two equations eliminates one variable.

  (s +h) +(s -h) = (235) +(59)

  2s = 294 . . . . simplify

  s = 147 . . . . . .divide by 2

  h = 147 -59 = 88 . . . . h is 59 less

147 sodas and 88 hot dogs were sold.

__

<em>Additional comment</em>

The solution to a "sum and difference" problem is always the same. One of the numbers is half the sum of those given, and the other is half their difference. ((235-59)/2 = 88)

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NISA [10]

Answer:

\displaystyle \large{\sum_{n=1}^{42}(6n-1)

Step-by-step explanation:

Given:

  • Series 5+11+17+...+251

To find:

  • Summation notation of the given series

Summation Notation:

\displaystyle \large{\sum_{k=1}^n a_k}

Where n is the number of terms and \displaystyle \large{a_k} is general term.

First, determine what kind of series it is, there are two main series that everyone should know:

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A series that has common difference.

  • Geometric Series

A series that has common ratio.

If you notice and keep subtracting the next term with previous term:

  • 11-5 = 6
  • 17-11 = 6

Two common difference, we can in fact say that the series is arithmetic one. Since we know the type of series, we have to find the number of terms.

Now that brings us to arithmetic sequence, we know that first term is 5 and last term is 251, we’ll be finding both general term and number of term using arithmetic sequence:

<u>Arithmetic Sequence</u>

\displaystyle \large{a_n=a_1+(n-1)d}

Where \displaystyle \large{a_n} is the nth term, \displaystyle \large{a_1} is the first term and \displaystyle \large{d} is the common difference:

So for our general term:

\displaystyle \large{a_n=5+(n-1)6}\\\displaystyle \large{a_n=5+6n-6}\\\displaystyle \large{a_n=6n-1}

And for number of terms, substitute \displaystyle \large{a_n} = 251 and solve for n:

\displaystyle \large{251=6n-1}\\\displaystyle \large{252=6n}\\\displaystyle \large{n=42}

Now we can convert the series to summation notation as given the formula above, substitute as we get:

\displaystyle \large{\sum_{n=1}^{42}(6n-1)

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2 years ago
Convert the decimal to a fraction in simplest form:
Shkiper50 [21]

Answer:

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Step-by-step explanation:

Given the decimal

0.333

Multiply and divide by 10 for every number after the decimal point.

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Thus,

0.333=\frac{0.333\cdot \:\:1000}{1000}

         =\frac{333}{1000}         ∵ 0.333×1000 = 333

Let us check if we can reduce the fraction \frac{333}{1000}

For this, we need to find a common factor of 333 and 1000 in order to cancel it out.

But, first, we need to find the Greatest Common Divisor (GCD) of 333, 1000

<u>Greatest Common Divisor (GCD) : </u>

The GCD of a, b is the largest positive number that divides both a and b without a remainder.

Prime Factorization of 333:      3 · 3 · 37

Prime Factorization of 1000:      2 · 2 · 2 · 5 · 5 · 5

As there is no common factor for 333 and 1000, therefore, the GCD is 1.

Important Tip:

  • As GCD is 1, therefore the fraction can not be simplified.

Therefore, decimal 0.333 to a fraction in simplest form is:   \frac{333}{1000}

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Answer:

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