What is the gradient of the graph shown?
1 answer:
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The given points are
P = (-4,11)
Q = (-5,8)
The x-component of vector QP is
-4 - (-5) = 1
The y-component of vector QP is
11 - 8 = 3
The vector QP is
(1,3) or
The magnitude of the vector is
√(1² + 3²) = √(10)
Answer:
The magnitude is √(10).
P = (-4,11)
Q = (-5,8)
The x-component of vector QP is
-4 - (-5) = 1
The y-component of vector QP is
11 - 8 = 3
The vector QP is
(1,3) or
The magnitude of the vector is
√(1² + 3²) = √(10)
Answer:
The magnitude is √(10).
To start, we're given the range that x lies in: from -1 to 4. We know from the fact that 
that -1 will be <em /><em>included</em> in that range, so we mark -1 on the number line with a solid circle. We also know from 
that, while x can be any value <em>up to</em> 4, it does not <em>include </em>4. We indicate this by drawing a hollow circle around 4 on the number line. Since x can be <em>any value within this range</em>, we make that fact clear by drawing a bold line between the points -1 and 4 on the number line. I've attached an image of what our final graph would look like.
