Which segment is a perpendicular bisector of triangle ABC? helpp due 20 mins..

Mathematics

1 answer:

mojhsa [17]2 years ago

7 0

Answer:

SR and RZ

Step-by-step explanation:

A perpendicular bisector is a line segment that passes through the midpoint of a side of a triangle. In other words, If it goes through a side, it should split the segment in half perfectly. Furthermore, it must be perpendicular to the side it passes through (it should form a ninety-degree angle with the side). Given these two rules, one can say that one of the perpendicular bisectors is SR. SR forms a right angle with (and is thus perpendicular to) side AB. Furthermore, AS is congruent to (has the same length as) SB, which means SR cuts AB in half exactly. Another bisector would be RZ (for similar reasoning). Let me know if that doesn't make sense.

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Galina-37 [17]

The answer is
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6 0

3 years ago

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DIA [1.3K]

Answer:

Circumference
Area
Circumference

Step-by-step explanation:

Circumference would be if the situation is asking for the amount of something around the edge. For example, the number of tiles to be placed around the swimming pool would be asking for circumference.

Area would be if the situation is asking for the amount of something spread through the entire item. For example, the amount of water total in a swimming pool would be asking for area.

Hope it helps!

3 0

3 years ago

HELP ASAP FOR BRAINLIEST!

salantis [7]

Answer:

make sure calculator is in "radians" mode
use the cos⁻¹ function to find cos⁻¹(.23) ≈ 1.338718644

Step-by-step explanation:

A screenshot of a calculator shows the cos⁻¹ function (also called arccosine). It is often a "2nd" function on the cosine key. To get the answer in radians, the calculator must be in radians mode. Different calculators have different methods of setting that mode. For some, it is the default, as in the calculator accessed from a Google search box (2nd attachment).

The third attachment shows a graph of the cosine function (red) and the value 0.23 (dashed red horizontal line). Everywhere that line intersects the cosine function is a value of A such that cos A = 0.23. There are an infinite number of them. You need to know about the symmetry and periodicity of the cosine function to find them all, given that one of them is A ≈ 1.339.

The solution in the 4th quadrant is at 2π-1.339, and additional solutions are at these values plus 2kπ, for any integer k.

Also in the third attachment is a graph of the inverse of the cosine function (purple). The dashed purple vertical line is at x=0.23, so its intersection point with the inverse function is at 1.339, the angle at which cos(x)=0.23. The dashed orange graph shows the inverse of the cosine function, but to make it be single-valued (thus, a function), the arccosine function is restricted to the range 0 ≤ y ≤ π (purple).

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So, the easiest way to answer the problem is to use the inverse cosine function (cos⁻¹) of your scientific or graphing calculator. (Always make sure the angle mode, degrees or radians, is appropriate to the solution you want.) Be aware that the cosine function is periodic, so there is not just one answer unless the range is restricted.

I keep myself "unconfused" by reading cos⁻¹ as the angle whose cosine is. As with any inverse functions, the relationship with the original function is ...

cos⁻¹(cos A) = A

cos(cos⁻¹ a) = a