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2 years ago

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Of the following points, name all that lie on the same horizontal line

1 answer:

lina2011 [118]2 years ago

5 0

Answer:

(-5,7) (5,-7)

Step-by-step explanation:

When you are told to lable, show or name the points that lie on a horizontal line, it basically means that; when a line is drawn, it passes through the selected points without changing the direction when joined together (horizontally).

From the above problem, (-5,7) and (5,-7) lie in the same horizontal line.

For (7,-5) and (-7,5) lie in the same vertical line.

Thereforeour, the answer is (-5,7) (5,-7).

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Hi who can help me do this 2quetion,I will mark brainlest

hodyreva [135]

Step-by-step explanation:

$8. log_{10}(2.15) = 0.332 \: then \: log_{10}(21500) = ..... \\ log(21500) = log(2.15 \times 10000) \\ = log(2.15) + log(10000) \\ = log_{10}(2.15) + log_{10}( {10}^{4} ) \\ = 0.332 + 4 log_{10}(10) \\ = 0.332 + 4(1) \\ log_{10}(21500) = 4.332$

9. log(2)=a, log(3)=b, then log(36)=______

log(36) = log(6*6) = log(6) + log(6)

log(36)= log(6) + log(6)

log(36) = log(3*2) + log(3*2)

log(36) = (log(3) + log(2)) + (log(3) + log(2))

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log(36) = a + b + b + a

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5 0

2 years ago

Read 2 more answers

Joe paid $14.00 for a board game. This is 70% of the original price ? $4.20 $20.00 $9.80 $21.00

meriva

I believe this question should be from an I-Ready test. The answer would be $20.00. Because 70% of 20.00 is 14

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3 years ago

Which expression would be easier to simplify if you used the associative property to change the grouping? O A. (170 + 30) – 41 O

jekas [21]

Answer:

A.(170+30)-41

Step-by-step explanation:

(170+30)-41=170+(30-41)

200-41=170+(-11)

159=170-11

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2 years ago

Suppose that scores on the mathematics part of a test for eighth-grade students follow a Normal distribution with standard devia

riadik2000 [5.3K]

Answer:

We need an SRS of scores of at least 153.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.9}{2} = 0.05$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.05 = 0.95$ , so $z = 1.645$

Now, find M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

How large an SRS of scores must you choose?

This is at least n, in which n is found when $M = 20, \sigma = 150$ . So

$M = z*\frac{\sigma}{\sqrt{n}}$

$20 = 1.645*\frac{150}{\sqrt{n}}$

$20\sqrt{n} = 1.645*150$

$\sqrt{n} = \frac{1.645*150}{20}$

$\sqrt{n} = 12.3375$

$(\sqrt{n})^{2} = (12.3375)^{2}$

$n = 152.2$

Rounding to the next whole number, 153

We need an SRS of scores of at least 153.

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3 years ago

Harry is a builder.

sergij07 [2.7K]

Answer:

£39.95

Step-by-step explanation:

multiply it by £7.99×5

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2 years ago