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NikAS [45]
2 years ago
12

Operational level management can be supported by the systems except Select one: 01. Transaction Processing System 2. Manufacturi

ng Information System 3. Executive support system 4. Financial management system ​
Computers and Technology
1 answer:
lidiya [134]2 years ago
7 0

Answer:

01×3=3

=3

Explanation:

mousamyuig9uuygytyugghbhhbhhbhh

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If all of Earth's history were squeezed into one 12-hour period, how long ago did Precambrian time end? How long did the Cenozoi
Jet001 [13]

Answer:

That it

Explanation:

There have been mass extinctions during the Cenozoic as there were during the Mesozoic and Paleozoic, but not as many animals and plants have disappeared. Finally, humanity appeared during the last two million years.The human lineage only diverged from our most recent common ancestor about 5 million years ago; less than half of 1% of that time, and modern Homo sapiens is only between 200,000 and 50,000 years old, depending on your definition.

7 0
3 years ago
Which port must be open on your router to allow you to upload device configuration and firmware updates using trivial file trans
Vika [28.1K]

Answer:

UDP Port 69

<em>Trivial file transfer protocol (TFTP) operates over UDP port 69.</em>

Explanation:

UDP port 69 uses the Datagram Protocol, a communications protocol for the Internet network layer, transport layer, and session layer. This protocol when used over PORT 69 makes possible the transmission of a datagram message from one computer to an application running in another computer. UDP is used with <em>IP (the Internet Protocol)</em> and UDP Port 69 is <em>connectionless </em>which means it does not give reliable communication; it’s up to the application that received the message on Port 69 to process any errors and verify correct delivery.

3 0
3 years ago
Write a function wordcount() that takes the name of a text file as input and prints the number of occurrences of every word in t
o-na [289]

Answer:

I am writing a Python program. Let me know if you want the program in some other programming language.        

import string  #to use string related functions

def wordcount(filename):  # function that takes a text file name as parameter and returns the number of occurrences of every word in file

   file = open(filename, "r")  # open the file in read mode

   wc = dict()  # creates a dictionary

   for sentence in file:  # loop through each line of the file

       sentence = sentence.strip()  #returns the text, removing empty spaces

       sentence=sentence.lower() #converts each line to lowercase to avoid case sensitivity

       sentence = sentence.translate(sentence.maketrans("", "", string.punctuation))  #removes punctuation from every line of the text file

       words = sentence.split(" ")  # split the lines into a list of words

       for word in words:  #loops through each word of the file

           if len(word)>2:  #checks if the length of the word is greater than 2

               if word in wc:  # if the word is already in dictionary

                   wc[word] = wc[word] + 1  #if the word is already present in dict wc then add 1 to the count of that word

               else:  #if the word is not already present

                   wc[word] = 1  # word is added to the wc dict and assign 1 to the count of that word                

   for w in list(wc.keys()):  #prints the list of words and their number of occurrences

       print(w, wc[w])  #prints word: occurrences in key:value format of dict        

wordcount("file.txt") #calls wordcount method and passes name of the file to that method

Explanation:

The program has a function wordcount that takes the name of a text file (filename) as parameter.

open() method is used to open the file in read mode. "r" represents the mode and it means read mode. Then a dictionary is created and named as wc. The first for loop, iterates through each line (sentence) of the text file. strip() method is used to remove extra empty spaces or new line character from each sentence of the file, then each sentence is converted to lower case using lower() method to avoid case sensitivity. Now the words "hello" and "Hello" are treated as the same word.

sentence = sentence.translate(sentence.maketrans("", "", string.punctuation))  statement uses two methods i.e. maketrans() and translate(). maketrans() specifies the punctuation characters that are to be deleted from the sentences and returns a translation table. translate() method uses the table that maketrans() returns in order to replace a character to its mapped character and returns the lines of text file after performing these translations.

Next the split() method is used to break these sentences into a list of words. Second for loop iterates through each word of the text file. As its given to ignore words of length 2 or less, so an IF statement is used to check if the length of word is greater than 2. If this statement evaluates to true then next statement: if word in wc:   is executed which checks if the word is already present in dictionary. If this statement evaluates to true then 1 is added to the count of that word. If the word is not already present  then the word is added to the wc dictionary and 1 s assigned to the count of that word.

Next the words along with their occurrences is printed. The program and its output are attached as screenshot. Since the frankenstein.txt' is not provided so I am using my own text file.

4 0
3 years ago
If you feel your friend had a negative digital identity, what would you do or tell them in order to help them have a positive di
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Have them post more positive outcomes and help them understand that what they post stays there forever
4 0
3 years ago
Read 2 more answers
Program to calculate series 10+9+8+...+n" in java with output
avanturin [10]

Answer:

import java.util.Scanner;

class Main {

 public static int calcSeries(int n) {

   int sum = 0;

   for(int i=10; i>=n; i--) {

     sum += i;

   }

   return sum;

 }

 public static void main(String[] args) {

   Scanner reader = new Scanner(System.in);

   int n = 0;

   do {

     System.out.print("Enter n: ");

     n = reader.nextInt();

     if (n >= 10) {

       System.out.println("Please enter a value lower than 10.");

     }

   } while (n >= 10);

   reader.close();

   System.out.printf("sum: %d\n", calcSeries(n));

 }

}

5 0
3 years ago
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