All categories

2 years ago

Please help me with this (i attached photos to cause less confusion) Thanks :) 25 Points!!!

Mathematics

2 answers:

Arlecino [84]2 years ago

5 0

Horizontal line has zero slope
slope=rise/run=0
#1) and #2) both are slope=0
greatest y value is +4 from x=3 to 4.
then least y value is -3 from x=-4 to -3.

navik [9.2K]2 years ago

4 0

Answer:

See below

Step-by-step explanation:

The first two questions are slope = 0

a horizontal line has zero slope

slope = rise/run = 0 / run = 0

Greatest y value is + 4 from x = 3 to 4

the least y value is -3 fro x = -4 to -3

You might be interested in

Answer this for brainliest!!

Zinaida [17]

The answer is f(x)= 2,000,000 (1.02)^x.

8 0

3 years ago

Read 2 more answers

Help it’s due tmr I can’t get a dt!

hichkok12 [17]

Answer:

Tisco

Step-by-step explanation:

T=1.65x4 is 6.6

A=1.36x5 is 6.8

6.8>6.6

sry if wrong

3 0

3 years ago

Xy′ = √(1 − y2 ), y(1) = 0

tigry1 [53]

Answer:

y=sin(ln(x))

Step-by-step explanation:

First, we have to order the terms as follows and express y' as dy / dx:

$x*\frac{dy}{dx} =\sqrt{(1-y^{2} )} \\\frac{x}{dx}=\frac{dy}\sqrt{(1-y^{2} )}}\\\frac{dx}{x}=\frac{dy}{\sqrt{(1-y^{2} )} }$

Then, we have to integrate

$\int{\frac{dx}{x}=\int{\frac{dy}{\sqrt{(1-y^{2} )} }$

with this solution after integration:

$ln(x)+C1=arcsin(y)+C2$

Then, we have to reorder

$arcsin(y)=ln(x)+C$

and applied Sin function on both sides

$sin(arcsin(y))=sin(ln(x)+C)\\y=sin(ln(x)+C)$

To define the value of C, we use the known point y(1)=0 and replace in the equation

$y=sin(ln(x)+C)\\0=sin(ln(1)+C)\\0=sin(0+C)\\0=sin(C)\\C=arcsin(0)\\C=0$

The function that proves that differential equation is

$y=sin(ln(x))$

6 0

3 years ago

A street lamp casts a shadow 31.5 feet long, while an 8 foot-tall street sign casts a shadow of 14 feet long. What is the length

sergeinik [125]

Answer:

The answer to your question is the height of the lamp is 18.2 ft

Step-by-step explanation:

Data

Street lamp shadow = 31.5 ft

Street sign height = 8 ft

Street sign shadow = 14 ft

Street lamp height = x

Process

1.- To find the height of the lamp use proportions. In this kind of problem, we do not look for the length, but the shadow.

Street lamp height/street lamp shadow = street sign height/street sign

shadow

Substitution

x / 31.5 = 8 / 14

Solve for x

x = (31.5)(8) / 14

Simplification

x = 254.4 / 14

Result

x = 18.2 ft

4 0

3 years ago

Plz do both of them for me and even show the work plzzzzzz

Vinvika [58]

Answer:

(a)= option 3

(b)= option 3

Step-by-step explanation:

(A) It is given that a sequence is defined by the recursive function $a_{1}=1$ and $a_{n}=a_{n-1}+n$

Now, substituting the value of n=2 in above equation,

$a_{2}=a_{1}+2$

$a_{2}=1+2$

$a_{2}=3$

Again putting n=3,

$a_{3}=a_{2}+3$

$a_{3}=3+3$

$a_{2}=6$

Putting n=4,

$a_{4}=a_{3}+4$

$a_{4}=6+4$

$a_{4}=10$

Putting n=5,

$a_{5}=a_{4}+5$

$a_{5}=10+5$

$a_{5}=15$

Putting n=6,

$a_{6}=a_{5}+6$

$a_{6}=15+6$

$a_{6}=21$

Putting n=7,

$a_{7}=a_{6}+7$

$a_{7}=21+7$

$a_{7}=28$

Hence, option 3 is correct.

(B) The given sequence is :

5, -10, 20, -40, 80.....

Since, the given sequence is GP, therefore

$a_{1}=5$ and r=-2

The nth term is given by:

$a_{n}=a_{1}r^{n-1}$

For fifteenth term, put n=15 in above equation, we get

$a_{15}=5(-2)^{14}$

= $5{\times}16384$

= $81920$

Hence, the fifteenth term is 81920.

Option 3 is correct.

5 0

3 years ago