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2 years ago

12

Point p has coordinates (-4,-2) and point q has coordinates (4,3) calculate the shortest distance between P and Q. Give your ans

wer to 1 decimal place

1 answer:

IRINA_888 [86]2 years ago

5 0

Answer:

distance = 9.4 units

Step-by-step explanation:

* using the distance formula *

d =

$\sqrt{(x2 - x1 )^{2} + (y2 - y1)^{2} }$

$\sqrt{( - 4 - 4) ^{2} + ( - 2 - 3) ^{2} }$

= 9.4 units

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The function h(x) is a transformation of the square root parent function,

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The function h(x) is a transformation of the square root parent function,

f(x)=√x. The function is h(x) A: √x+5.

<h3>What is Transformations?</h3>

Transformations come in the form;

y =√(x-h) +k,

where h is responsible for left-right movements, and k is responsible for up-down movements.

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2 years ago

Which point on the graph of g(x)=(1/5)^x? HELPP

Cloud [144]

Answer:

(-1,5) and $(3, \frac{1}{125})$ are points on the graph

Step-by-step explanation:

Given

$g(x) = \frac{1}{5}^x$

Required

Determine which point in on the graph

To get which of point A to D is on the graph, we have to plug in their values in the given expression using the format; (x,g(x))

A. (-1,5)

x = -1

Substitute -1 for x in $g(x) = \frac{1}{5}^x$

$g(x) = \frac{1}{5}^{-1}$

Convert to index form

$g(x) = 1/(\frac{1}{5})$

Change / to *

$g(x) = 1*(\frac{5}{1})$

$g(x) = 5$

This satisfies (-1,5)

<em>Hence, (-1,5) is on the graph</em>

<em></em>

B. (1,0)

x = 1

Substitute 1 for x

$g(x) = \frac{1}{5}^x$

$g(x) = \frac{1}{5}^1$

$g(x) = \frac{1}{5}$

<em>(1,0) is not on the graph because g(x) is not equal to 0</em>

C. $(3, \frac{1}{125})$

x = 3

Substitute 3 for x

$g(x) = \frac{1}{5}^x$

$g(x) = \frac{1}{5}^3$

Apply law of indices

$g(x) = \frac{1}{5} * \frac{1}{5} * \frac{1}{5}$

$g(x) = \frac{1}{125}$

This satisfies $(3, \frac{1}{125})$

<em>Hence, </em> $(3, \frac{1}{125})$ <em> is on the graph</em>

<em></em>

D. $(-2, \frac{1}{25})$

x = -2

Substitute -2 for x

$g(x) = \frac{1}{5}^x$

$g(x) = \frac{1}{5}^{-2}$

Convert to index form

$g(x) = 1/(\frac{1}{5}^2)$

$g(x) = 1/(\frac{1}{5}*\frac{1}{5})$

$g(x) = 1/(\frac{1}{25})$

Change / to *

$g(x) = 1*(\frac{25}{1})$

$g(x) = 25$

This does not satisfy $(-2, \frac{1}{25})$

<em>Hence, </em> $(-2, \frac{1}{25})$ <em> is not on the graph</em>

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4 years ago