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Korolek [52]
1 year ago
12

Point p has coordinates (-4,-2) and point q has coordinates (4,3) calculate the shortest distance between P and Q. Give your ans

wer to 1 decimal place
Mathematics
1 answer:
IRINA_888 [86]1 year ago
5 0

Answer:

distance = 9.4 units

Step-by-step explanation:

* using the distance formula *

d =

\sqrt{(x2 - x1 )^{2} + (y2 - y1)^{2} }

\sqrt{( - 4 - 4) ^{2} + ( - 2 - 3) ^{2} }

= 9.4 units

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Please help!!! ive been stuck on this for 30 minutes now!
max2010maxim [7]

Answer:

f^-1 = 4(x-3)

Step-by-step explanation:

If f(x) = 1/4(x) + 3 we ned to find f^-1.

To find the inverse function, we need to solve the equation for "x", as follows:

f(x) = 1/4(x) + 3

y = 1/4(x) + 3

y-3 = 1/4(x)

4(y-3) = x

Now, change the "x" for an "y". And change the "y" for an "x":

4(x-3) = y

The solution is the last one.

7 0
2 years ago
This is 10 points plz help ( ONLY ANSWER THIS IF YOU HAVE AN EXPLANATION AND IF YOU KNOW WHAT THE ANSWER IS)
Alenkinab [10]

Answer:

d = x + 90

Step-by-step explanation:

Total dollars to be paid by Mr. Sykes = Rent for the boat for 3 hours + cost of damage

= 90 + x

6 0
2 years ago
Read 2 more answers
Find the cosine of the angle between the planes x+y+z=0 and 4x+3y+z=1.<br><br> Answer: cosθ=
marta [7]

The angle between the planes is the same as the angle between their normal vectors, which are

<em>n</em><em>₁</em> = ⟨1, 1, 1⟩

<em>n</em><em>₂</em> = ⟨4, 3, 1⟩

The angle <em>θ</em> between the vectors is such that

⟨1, 1, 1⟩ • ⟨4, 3, 1⟩ = ||⟨1, 1, 1⟩|| ||⟨4, 3, 1⟩|| cos(<em>θ</em>)

Solve for cos(<em>θ</em>) :

4 + 3 + 1 = √(1² + 1² + 1²) √(4² + 3² + 1²) cos(<em>θ</em>)

8 = √3 √26 cos(<em>θ</em>)

cos(<em>θ</em>) = 8/√78

4 0
2 years ago
An object is propelled upward from the top of a 300 foot building. The path that the object takes as it falls to the ground can
serg [7]

Answer:

As per the statement:

The path that the object takes as it falls to the ground can be modeled by:

h =-16t^2 + 80t + 300

where

h is the height of the objects and

t is the time (in seconds)

At t = 0 , h = 300 ft

When the objects hit the ground, h = 0

then;

-16t^2+80t+300=0

For a quadratic equation: ax^2+bx+c=0         ......[1]

the solution for the equation is given by:

x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}

On comparing the given equation with [1] we have;  

a = -16 ,b = 80 and c = 300

then;

t= \frac{-80\pm \sqrt{(80)^2-4(-16)(300)}}{2(-16)}

t= \frac{-80\pm \sqrt{6400+19200}}{-32}

t= \frac{-80\pm \sqrt{25600}}{-32}  

Simplify:

t = -\frac{5}{2} = -2.5 sec and t = \frac{15}{2} = 7.5 sec

Time can't be in negative;

therefore, the time it took the object to hit the ground is 7.5 sec

8 0
3 years ago
What are the coordinates of (2,3) after a translation of 2 units left and then a rotation of 90 in a counterclockwise rotation a
eimsori [14]
2 units left would make it be 0,3 and a rotation of 90 degrees counterclockwise about the origin would make it -3,0
3 0
2 years ago
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