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lilavasa [31]
2 years ago
14

Need number 8 please!!

Mathematics
1 answer:
luda_lava [24]2 years ago
3 0

Using translation concepts, the graph of function g(x) = f(x) - 2 = x² - 2 is given at the end of the question.

<h3>What is a translation?</h3>

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

In this problem, the functions are given as follows:

  • f(x) = x².
  • g(x) = f(x) - 2 = x² - 2.

Which means that g(x) is a shift down of 2 units of f(x), as given by the graph in the end of the question.

More can be learned about translation concepts at brainly.com/question/4521517

#SPJ1

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Suppose that 3 balls are chosen without replacement from an urn consisting of 5 white and 8 red balls. Let Xi equal 1 if the ith
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Answer:

The joint probability mass function table is provided below.

Step-by-step explanation:

The experiment consist of drawing 3 balls from an urn containing 5 white and 8 red balls.

The random variable <em>Xi</em> is defined as follows:

<em>Xi</em> = 1; if the ith ball is white

<em>Xi</em> = 0; otherwise.

Then <em>X</em>₁ = the 1st ball is white and <em>X</em>₂ = the 2nd ball is white.

The sample space is as follows:

S = {(X₁ = 0, X₂ = 0), (X₁ = 0, X₂ = 1), (X₁ = 1, X₂ = 0), (X₁ = 1, X₂ = 1)}

Compute the probability of each event in the sample space as follows:

P(X_{1} = 0, X_{2}= 0)=\frac{8}{13} \times\frac{7}{12}=\frac{14}{39}

P(X_{1} = 0, X_{2}= 1)=\frac{8}{13} \times\frac{5}{12}=\frac{10}{39}

P(X_{1} = 1, X_{2}= 0)=\frac{5}{13} \times\frac{8}{12}=\frac{10}{39}

P(X_{1} = 1, X_{2}= 1)=\frac{5}{13} \times\frac{4}{12}=\frac{5}{39}

The joint probability mass function table is provided below.

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Answer:

3. rolling a sum of 20 with two standard dice

Step-by-step explanation:

If something has a probability of 0 then there is no chance of it happening

A standard die goes up to 6. The max sum you can get by rolling two dice would be 12 as 6 + 6 = 12. So you have no chance of rolling a sum of 20 with two standard dice therefore the probability would be 0.

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How do we Simplify each sum
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Answer:

The answer is 10m² - 1

Step-by-step explanation:

1) Remove parentheses.

{4m}^{2}  -  {5m}^{4}  - 5 +  {5m}^{4}  +  {6m}^{2}  + 4

2) Collect like terms.

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3) Simplify.

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<u>Therefor</u><u>,</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>10m</u><u>²</u><u> </u><u>-</u><u> </u><u>1</u><u>.</u>

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