Comparing x-1 with x-a then x=1
1^3+p*1^2-1-2=0
1+2p-3=0
2p=3-1
P=2/2
P=1
:.p=1
Answer:2
Step-by-step explanation:
Answer: The answer is 
Step-by-step explanation: Given that Cooper is studying two fractions and both are less than 1. The first fraction has a denominator of 4 and rounds to 1.
So, let the first fraction be

and surely it will rounds to 1.
Also, the second fraction has a denominator of 6 and the same numerator as the first fraction.
Therefore, the second fraction will be

Thus, the second fraction will be closest to 
{5x + 4y = -30
{3x - 9y = -18 | : 3
{5x + 4y = -30
{x - 3y = -6 | + 3y
{5x + 4y = -30
{x = 3y - 6
{5(3y - 6) + 4y = -30
{x = 3y - 6
{15y - 30 + 4y = -30 | + 30
{x = 3y - 6
{19y = 0 | : 19
{x = 3y - 6
{y = 0
{x = 3 · 0 - 6
{y = 0
{x = -6