Question

What is the x-coordinate of the point that divides the directed line segment from k to j into a ratio of 1:3? x = (startfraction m over m n endfraction) (x 2 minus x 1) x 1 –1 3 7 11

Answer 1

The x-coordinate of the point which divide the line segment is 3.

Given the coordinates in the figure are J(1,-10) and K(9,2) and the 1:3 is the ratio in which the line segment is divided.

When the ratio of the length of a point from both line segments is m:n, the Sectional Formula can be used to get the coordinate of a point that is outside the line.

To find the x-coordinate we will use the formula x=(m/(m+n))(x₂-x₁)+x₁.

Here, m:n=1:3 and x₁=1 from the point J(1,-10) and x₂=9 from the point K(9,2).

Now, we will substitute these values in the formula, we get

x=(1/(1+3))(9-1)+1

x=(1/4)(8)+(1)

x=8/4+1

x=3

Hence, the x-coordinate of the point that divides the directed line segment from k to j into a ratio of 1:3 is 3 units.

Learn about line segments from here brainly.com/question/10240790

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