Answer:
35 glasses of classic milk tea
15 glasses of flavored milk tea
Step-by-step explanation:
You sold 50 glasses of classic and flavored milk tea.
c + f = 50
You made 4700 when classic tea costs 100 and flavored tea costs 80.
100c + 80f = 4700
Use this system of equation to solve. Use substitution. Rearrange the first equation so that it is equal to c. Then, plug the c-value into the second equation.
c + f = 50
c = 50 - f
100c + 80f = 4700
100(50 - f) + 80f = 4700
5000 - 100f + 80f = 4700
5000 - 20f = 4700
-20f = -300
f = 15
Plug the f-value into one of the equations and solve for c.
c + f = 50
c + 15 = 50
c = 35
35 glasses of classic milk tea and 15 glasses of flavored milk tea were sold.
Answer:
33% or .33
Step-by-step explanation:
Divide 1/3 = .3333 (repeating). I would round to the nearest hundreths place:
1/3 = .33
For the precentage, multiple 0.33 by 100:
100 * 0.33 = 33%
Answer:
y=1x-6
Step-by-step explanation:
luckily i love math, plz put as brainliest
Answer:
x-10 +x = 8 + 2x - 18
Step-by-step explanation:
The solution is the point of intersection between the two equations.
Assuming you have a graphing calculator or a program to lets you graph equations (I use desmos) you simply put in the equetions and note down the coordinates of the point of intersection.
In the graph the first equation is in blue and the second in red.
The point of intersection = the solution = (-6 , -1)
If you dont have access to a graphing calculator you could draw the graphs by hand;
1) Draw a table of values for each equation; you do this by setting three or four values for x and calculating its image in y (you can use any values of x)
y = 0.5 x + 2 (Im writing 0.5 instead of 1/2 because I find its easier in this format)
x | y
-1 | 1.5 * y = 0.5 (-1) + 2 = 1.5
0 | 2 * y = 0.5 (0) + 2 = 2
1 | 2.5 * y = 0.5 (1) + 2 = 2.5
2 | 3 * y = 0.5 (2) + 2 = 3
y = x + 5
x | y
-1 | 4 * y = (-1) + 5 = 4
0 | 5 * y = (0) + 5 = 5
1 | 6 * y = (1) + 5 = 6
2 | 7 * y = (2) + 5 = 7
2) Plot these point on the graph
I suggest to use diffrent colored points or diffrent kinds of point markers (an x or a dot) to avoid confusion about which point belongs to which graph
3) Using a ruler draw a line connection all the dots of one graph and do the same for the other
4) The point of intersection is the solution