The given equation solved for A is A = (T + 5)/ B
<h3>Solving linear equation</h3>
From the question, we are to solve the given equation for A
To solve the equation for A, we will simply make A the subject of the equation
The given equation is
T = AB - 5
Solving for A
T = AB - 5
Add 5 to both sides of the equation
T + 5 = AB - 5 + 5
T + 5 = AB
Divide both sides of the equation by B
That is,
(T + 5)/B = AB/B
(T + 5)/B = A
∴ A = (T + 5)/ B
Hence, the given equation solved for A is A = (T + 5)/ B
Learn more on Solving linear equation here: brainly.com/question/1531728
#SPJ1
"h and k cannot both equal zero" -- yes, it can. if the vertex of a parabola is at (0, 0), there's nothing incorrect/invalid about that!!
"k and c have the same value" -- k and c do not have the same value. "k" is the y-value of the vertex and c is the constant in your quadratic equation, and the constant is not necessarily the y-value.
"the value of a remains the same" -- this is true. the a's in your equations are the same values, because the a-value is the coefficient of the x-variable in both equations. y = a(x - h)^2 and y = ax^2 -- both of these have a applying to your x-variables.
"h is equal to one half -b" -- this isn't true. the formula for calculating the x value of the vertex (h is the x-value of the vertex) is h = (-b/2a). -b/2a is not the same as one half -b because this answer choice doesn't involve the a-value.
So first uadd 30 with 25 the the answer u get u multiply with 12 hope that helps
Answer:
b, c, d
Step-by-step explanation:
(y^2)^5 × y^8
Use the rule:
To get:
y^10, then, use the rule:
To eventually get:
y^(10+8) = y^18 or: y18 seeing as you wrote it like that.
