2. Each side of a pentagon is the same size.
4cm x 5 = 20cm or 4cm+4cm+4cm+4cm+4cm = 20cm
3. Each side of a square is the same size.
13yd x 4 = 52yd or 13yd+13yd+13yd+13yd = 52yd
4. Add all sides together.
12m+12m+30m+30m = 84m
5. Again add all sides together.
16yd+16yd+4yd+4yd = 40yd
6. Each side of a square is the same size.
7in x 4 = 28in. or 7in+7in+7in+7in = 28in
7. Add all sides together.
2cm+2cm+3cm+3cm = 10cm
8. Each side of a rhombus is the same size. A rhombus has 4 sides.
23in x 4 = 92in or 23in+23in+23in+23in = 92in
9. A regular octagon has 8 sides and each side is the same size.
9cm x 8 = 72cm
<h3>Answer:</h3>
All acute angles are 72.5°; all obtuse angles are 107.5°.
<h3>Explanation:</h3>
Angles on the same side of a transversal cutting parallel lines have measures that total 180°. If o and a represent the measures of the obtuse and acute angles, respectively, then we have ...
... o + a = 180
... o - a = 35
Adding these two equations gives ...
... 2o = 215
... 215/2 = o = 107.5 . . . . degrees
Then the other angle is ...
... a = 107.5 - 35 = 72.5 . . . . degrees
_____
All corresponding angles have the same measures. All vertical angles have the same measures. So the 8 angles that arise from the intersection of the transversal with these two parallel lines will have one or the other of these two measures.
Answer:
(-2,-110)
Step-by-step explanation:
First solve for x
20x−70=70x+30
x= -2
Now substitute x for -2
y=20x−70
y=20(-2)-70
y = -110
A) He wanted to create zero pairs on the left side of the equation to get a positive coefficient of x on the right side