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2 years ago

PLEASE HELP!!

Physics

2 answers:

Ivanshal [37]2 years ago

7 0

The coordinates of the image of point A of the dilated triangle becomes (3,3) where the image is from y axis.

Explanation:

Given-

scale factor = 2

length of base AB which corresponds the x axis is 1 unit

length of height BC which corresponds the y axis is 1 unit

Scale factor = new dimension/old dimension

For x axis-

2 = new dimension/ 1

new dimension for AB which corresponds the x axis is 2 units

For y axis-

2 = new dimension / y

new dimension for BC which corresponds the y axis is 2 units

The older coordinates for triangle ABC is (-2,2)

The new coordinates of the dilated triangle is (-3.3)

The coordinates of the image of point A of the dilated triangle becomes (3,3) where the image is from y axis.

sveta [45]2 years ago

3 0

Answer:

it is -4, 2

hope this helps

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3 years ago

The density of a material in CGS system of units is 4g cm-³. In a system of units in which unit of length is 10 cm and unit of m

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$\sf\underline{Solution:}$

Here , the density of the material is 4g cm³ but it is not given in CGS system.

$\sf{As\:we\:know\:that:}$

$\sf\bold{Density=}$ $\sf\dfrac{Mass}{Volume}$

$\space$

$\sf{Now,according \: to \:the\:question:}$

$\sf\small{Density\:of\:the\:material=4}$ $\sf\dfrac{g}{cm^2}$

$\space$

$\sf{It\:is\:given\:that:}$

In the system of units the mass is 100gram.

$\space$

Hence,

$\sf{The\:mass\:unit\:for\:4g=}$ $\sf\dfrac{4}{100}$ $\sf{units}$

$\space$

In the system of units,the length is 10cm.

Henceforth,

$\sf\small{The\:length \:for\:1cm\:units=}$ $\sf\dfrac{1}{10}$ $\sf{units}$

$\space$

☆ Substitute the required values in the given formula-

$\sf\purple{Density=}$ $\sf\dfrac\purple{Mass}\purple{volume}$

$\space$

$\sf\underline\bold{Density\:of\:the\:material:}$

= $\sf\dfrac{4/100}{1/10^3}$ $\sf\bold{units}$

$\space$

= $\sf\dfrac{4/100}{1/1000}$ $\sf\bold{units}$

$\space$

= $\sf\dfrac{4000}{100}$ $\sf\bold{units}$

$\space$

$\sf\underline\bold\blue{=40\:units}$

$\sf\small{Therefore,option\:2nd\:is\:correct!}$

_______________________________

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