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Vikentia [17]
2 years ago
15

Select the correct answer from each drop-down menu. the endpoints of the longest chord on a circle are (4, 5.5) and (4, 10.5). t

he center of the circle is at the point , and its radius is units. the equation of this circle in standard form is .
Mathematics
1 answer:
torisob [31]2 years ago
6 0

The equation of this circle in standard form is equal to (x - 4)² + (y - 8)² = 5².

Based on the calculations, the equation of this circle in standard form is equal to (x - 4)² + (y - 8)² = 5²

The equation of a circle.

Mathematically, the standard form of the equation of a circle is given by;

(x - h)² + (y - k)² = r²

Where:

h and k represent the coordinates at the center.

r is the radius of a circle.

The midpoint of the given points represents the center of this circle:

h = (4 + 4)/2 = 4

k = (5.5 + 10.5)/2 = 8

Next, we would determine the radius by using the distance formula for coordinates:

r = √[(x₂ - x₁)² + (y₂ - y₁)²]

r = √[(4 - 4)² + (10.5 - 5.5)²]

r = √[0² + 5²]

r = √25

r = 5 units.

Therefore, the equation of this circle in standard form is equal to (x - 4)² + (y - 8)² = 5².

Learn more about circle here: brainly.com/question/12823137

#SPJ4

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How many sixteenth notes would be needed to have the same duration as 3 quarter notes? Represent this as a fraction
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3 years ago
In ΔQRS, the measure of ∠S=90°, QR = 8.2 feet, and SQ = 4.2 feet. Find the measure of ∠R to the nearest degree.
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4 years ago
Which equation best represents the data in the table if the math grade y depends on the number of days absent x?
evablogger [386]

The equation y= -5/2x+90 best represents the data in the table. Option D is the correct answer.

<u>Step-by-step explanation</u>:

To find the correct equation out of the four options, substitute y= grade% and x= days absent.

<u>Check for option A)</u>

when x= 0, y= 2/5(0)+90 = 90. option A satisfies.

when x= 2, y= 2/5(2)+90 = (4/5)+90 ≠ 85. option A does not satisfy.

<u>Check for option B)</u>

when x= 0, y= -2/5(0)+90 = 90. option B satisfies.

when x= 2, y= -2/5(2)+90 = (-4/5)+90 ≠ 85. option B does not satisfy.

<u>Check for option C)</u>

when x= 0, y= 5/2(0)+90 = 90. option C satisfies.

when x= 2, y= 5/2(2)+90 = (5)+90 = 95 ≠ 85. option C does not satisfy.

<u>Check for option D)</u>

when x= 0, y= -5/2(0)+90 = 90. option D satisfies.

when x= 2, y= -5/2(2)+90 = (-5)+90 = 85. option D satisfies.

when x= 4, y= -5/2(4)+90 = (-5*2)+90 = -10+90 = 80. option D satisfies.

when x= 6, y= -5/2(6)+90 = (-5*3)+90 = -15+90 = 75. option D satisfies.

when x= 8, y= -5/2(8)+90 = (-5*4)+90 = -20+90 = 70. option D satisfies

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