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hodyreva [135]
2 years ago
10

Print out the following message three different ways. Please put a blank line inbetween your three solutions.

SAT
1 answer:
goblinko [34]2 years ago
8 0

Using the knowledge in computational language in python it is possible to write a code that print out the following message three different ways.

<h3>What is called print out?</h3>

A hard copy (or "hardcopy") is a printed copy of information from a computer. Sometimes referred to as a printout , a hard copy is so-called because it exists as a physical object.

<h3>Writting the code in python:</h3>

<em>#Output Way 1</em>

<em>print("Summer 2022\nBreak!")</em>

<em>print()   #Blank Line</em>

<em>#Output Way 2</em>

<em>lst1 = ['Summer', '2022', 'Break!']</em>

<em>print(lst1[0],lst1[1]+"\n"+lst1[2])</em>

<em>print()   #Blank Line</em>

<em>#Output Way 3</em>

<em>lst2 = ['Summer', '2022', 'Break!']</em>

<em>print(' '.join(lst2[0:2]),"\n"+''.join(lst2[2]))</em>

See more about python at brainly.com/question/13437928

#SPJ1

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<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

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In which:

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The margin of error is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In this problem:

  • The estimate of the proportion is of \pi = 0.8.
  • The desired margin of error is of M = 0.01.
  • 90% confidence level, hence\alpha = 0.9, z is the value of Z that has a p-value of \frac{1+0.9}{2} = 0.95, so z = 1.645.

Then, we solve for n to find the minimum sample size.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.01 = 1.645\sqrt{\frac{0.8(0.2)}{n}}

0.01\sqrt{n} = 1.645\sqrt{0.8(0.2)}

\sqrt{n} = \frac{1.645\sqrt{0.8(0.2)}}{0.01}

(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.8(0.2)}}{0.01}\right)^2

n = 4329.6

Rounding up, the smallest sample size required to obtain the desired margin of error is of 4330.

To learn more about the z-distribution, you can take a look at brainly.com/question/12517818

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