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jekas [21]
2 years ago
11

Determine if the following costs would be considered direct or indirect for a division which manufactures bicycles.

SAT
1 answer:
Fynjy0 [20]2 years ago
8 0

The classifications for each of the costs are respectively; Direct Materials, Direct Labor, Materials Overhead, Materials Overhead.

<h3>How to classify direct or Indirect Costs?</h3>

1. Frames and tires used in manufacturing bicycles; This cost would be classified as Direct materials.

2. Wages paid to production workers; This cost would be classified as Direct Labor as that is what it is used for.

3. Insurance on factory equipment and machinery; This cost will be classified as Manufacturing Overhead because it involves overheads necessary for manufacturing.

4. Depreciation on factory equipment; This cost will be classified as Manufacturing Overhead because it involves overheads necessary for manufacturing.

Complete question is;

Determine whether each of the following costs should be classified as direct materials, direct labor, or manufacturing overhead.

1. Frames and tires used in manufacturing bicycles.

2. Wages paid to production workers.

3. Insurance on factory equipment and machinery.

4. Depreciation on factory equipment.

Read more about classification of costs at; brainly.com/question/13219202

#SPJ1

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Complete the following steps to calculate the altitude of the parallelogram using area methods. The area of the sheet of paper i
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Based on the calculations, we have the following:

  1. The area of the sheet of paper is 96 square inches.
  2. The combined area of the triangle cutouts is equal to 36 square inches.
  3. The area of the parallelogram is equal to 60 square inches.
  4. The altitude of the parallelogram is equal to 6.51 square inches.

<u>Given the following data:</u>

  • Dimension of paper = 12-inch by 8-inch.

<h3>How to calculate the paper's area.</h3>

Mathematically, the area of the paper is given by this formula:

Area = length \times breadth\\\\Area = 12 \times 8

Area = 96 square inches.

<u>For the four (4) right triangles:</u>

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  • Dimension 2 = 3 inches by 6 inches.

Therefore, the combined area of the triangle cutouts is given by:

A_2= (2 \times \frac{1}{2} \times 2 \times 9) + 2 \times \frac{1}{2} \times 3 \times 6\\\\A_2=18+18\\\\A_2=36\;in^2

<h3>The area of the parallelogram.</h3>

This would be determined by subtracting the area of the four (4) right triangles from the areas of the paper as follows:

P = A_p -A_2\\\\P=96-36

P = 60 square inches.

<h3>The altitude of the parallelogram.</h3>

P = base \times altitude\\\\Altitude =\frac{P}{base} \\\\Altitude =\frac{60}{9.22}

Altitude = 6.51 square inches.

Read more on parallelogram here: brainly.com/question/4459854

<u>Complete Question:</u>

A parallelogram is cut out of a 12-inch by 8-inch sheet of paper. There are four right triangle remnants. Two have the dimensions 2 inches by 9 inches, and the other two have the dimensions 3 inches by 6 inches. The resulting parallelogram has a base of approximately 9.22 inches.

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