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2 years ago

Which is the graph of the inequality?

Mathematics

1 answer:

Sveta_85 [38]2 years ago

8 0

We can simplify the inequality to:

y > (-1/5)*x - 2

From that, we conclude that the correct option is the last one.

<h3>Which is the graph of the given inequality?</h3>

Here we have the inequality:

5y + x > -10

If we isolate y, we get:

y > (-10 - x)/5

y > (-1/5)*x - 2

Then the inequality will be a dashed/dotted line with a negative slope, that passes through the point (0, -2), such that the region above and to the right of the line is shaded.

From that we conclude that the correct option is the last one:

"Number graph ranging from negative ten to ten on the x and y axes. A dotted line passes through (zero, negative two) and (five, negative three). The area above the line is shaded gray."

If you want to learn more about inequalities:

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How do I write an explicit formula for this sequence? 2, 6, 18, 54, 162, ... I already know the common difference is x3.

uranmaximum [27]

If the common difference is 3 all you need to do is:
an=a1 - d(n-1)
2 - 3d + 3
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3 years ago

What’s 3x3x3x3x3x3x3

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Answer:

2,187

Step-by-step explanation:

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3 years ago

SunDrop Candies Inc claims that their 3 ounce bag of candies contains over 90 pieces of candy.

nlexa [21]

Answer:

a) X~N(μ;σ²)

b) [87.695 ; 89.464]

c) and d) check the explanation below

Step-by-step explanation:

Hello!

The objective of this experiment is to test if the claim of the company is correct and the 3-ounce bags of candies contain over 90 pieces of candy.

For this, a sample of 26 bags was taken and the number of candies per bag was counted.

The study variable is X: number of candy pieces in a 3 ounces bag.

Using the sample data I've made a Shapiro-Wilks test,

H₀: X has a normal distribution

H₁: X doesn't have a normal distribution

α: 0.05

p-value: 0.5675

Since the p-value is greater than the significance level, we can assume that the study variable has normal distribution:

X~N(μ;σ²)

To make this confidence interval, considering I only have sample data, I choose to use the Student t statistic.

Sample mean X[bar]= 88.58

Sample standard deviation S= 2.19

$t_{n-1;1-\alpha/2} = t_{25;0.975} = 2.060$

The formula for the interval is:

X[bar] ± $t_{n-1;1-\alpha/2}$ * (S/√n)

88.58 ± 2.060 * (2.19/√26)

[87.695 ; 89.464]

With a confidence level of 95%, you'd expect that the interval [87.69; 89.46] contains the value of the population mean of the number of candy pieces in a 3 ounces bag.

The SunDrop Candies' claim is that their 3 ounces bag contains over 90 pieces of candy. Symbolically: μ > 90

Since their claim would lead to a one-tailed hypothesis test and the calculated confidence interval is two-tailed, you cannot use it to decide whether or not the company's claim is true. But, seeing as the two bonds of the interval are below 90 you could think that the company's claim is not correct. Of course this is just an idea, you must perform a statistical test to test if the company is wrong or not and, of course, have a statistical backing of your conclusions.

I hope it helps!

6 0

3 years ago

Math help!! 5 questions!!! A classmate believes that a triangle can have both right angle and an obtuse angle. Which of the foll

nevsk [136]

A because it a triangle can not exceed 180

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3 years ago

If angle MNO is a rectangle, and MO = 54 , what is the length of overline NP ? A. 34 B. 22 C. 18 D. 108 E. 27 F. Cannot be deter

cricket20 [7]

Answer:

Option (E)

Step-by-step explanation:

LMNO is a rectangle.

MO = 54

By the property of a rectangle,

1). Diagonals are equal in length.

2). Diagonals equally bisect each other.

Since, MO = LN

Therefore, LN = 54

Since, NP = $\frac{1}{2}(LN)$

NP = $\frac{54}{2}$ = 27

Option (E) will be the correct option.

4 0

3 years ago