A jar has 16 marbles, 10 green, 2 blue, 4 red. what is the probability of randomly choosing a red marble then without putting it

Question

1 year ago

12

back, choosing a green marble?

1 answer:

marta [7] · Answer 1 · 2023-08-31T06:13:02+03:00

The probability of drawing a red marble and then a green marble is:

P = 1/6.

<h3>How to find the probability?</h3>

In the jar we have a total of 16 marbles, such that:

First, the probability of getting a red marble is give by the quotient between the number of red marbles and the total number of marbles:

p = 4/16 = 1/4

Now we need to draw a green one, the probability is computed in the same way, but this time there are 15 marbles, because we already took one.

q = 10/15

The joint probability (first drawing red, then green) is given by the product between the individual probabilities:

P = p*q = (1/4)*(10/15) = 10/60 = 1/6

If you want to learn more about probability:

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