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scoundrel [369]
2 years ago
12

A jar has 16 marbles, 10 green, 2 blue, 4 red. what is the probability of randomly choosing a red marble then without putting it

back, choosing a green marble?
Mathematics
1 answer:
marta [7]2 years ago
8 0

The probability of drawing a red marble and then a green marble is:

P = 1/6.

<h3>How to find the probability?</h3>

In the jar we have a total of 16 marbles, such that:

  • 10 are green.
  • 2 are blue
  • 4 are red.

First, the probability of getting a red marble is give by the quotient between the number of red marbles and the total number of marbles:

p = 4/16 = 1/4

Now we need to draw a green one, the probability is computed in the same way, but this time there are 15 marbles, because we already took one.

q = 10/15

The joint probability (first drawing red, then green) is given by the product between the individual probabilities:

P = p*q = (1/4)*(10/15) = 10/60 = 1/6

If you want to learn more about probability:

brainly.com/question/25870256

#SPJ1

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