Answer:
Perimeter of the rectangle = 6 x +20
Perimeter of the rectangle = 0<em> x² + 6 x + 20</em>
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the length of the rectangle = 2x +3
Given that the width of the rectangle = x +7
Perimeter of the rectangle = 2(length + width)
<u>Step(ii):-</u>
Perimeter of the rectangle = 2(length + width)
= 2(2 x +3 + x+7)
= 4x +6+2x+14
= 6 x +20
<u><em>Final answer:-</em></u>
Perimeter of the rectangle = 6 x +20
Perimeter of the rectangle = o x² + 6 x + 20
Volume of a sphere=(4/3)πr³ ⇒r=∛(3v/4π)
volume of a sphere=950 in³
Therefore:
r=∛(3*950 in³/4π)=6.09834... in≈6.1 in
answer: radius=6.1 in
The right answer should be y=3x+2
3a; Rectangle
3b; Square
3c;Trapezoid
