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anastassius [24]
1 year ago
5

Solve for x in the diagram below.

Mathematics
1 answer:
Sonbull [250]1 year ago
5 0
The answer is x=45…..
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What’s 20{5[100-3(25+35)+20]}
8_murik_8 [283]

Answer:

-6000

Step-by-step explanation:

20{5[100-3(25+35)+20]}            open the parenthesis

20{5[100-180+20]}         do the addition and subtraction in the square brackets

20{5[-60]}                        open the square brackets

20{-300}                           open curly brackets

-6000

6 0
2 years ago
Marked price = Rs 650 and Discount percentage = 2.5%. find selling price​
levacccp [35]

Answer:

The selling price is <u>Rs.633.75</u>.

<h3><u>Solution</u> :</h3>

Here we have given that :

  • \pink\star Marked Price = Rs.650
  • \pink\star Discount % = 2.5 %

We need to find the selling price.

Firstly, finding the discount by substituting the values in the formula :

{\longrightarrow{\sf{Discount = Marked \:  Price \times  Discount \%}}}

{\longrightarrow{\sf{Discount =650\times 2.5\%}}}

{\longrightarrow{\sf{Discount =650\times  \dfrac{2.5}{100}}}}

{\longrightarrow{\sf{Discount = \dfrac{650 \times 2.5}{100}}}}

{\longrightarrow{\sf{Discount = \dfrac{1625}{100}}}}

{\longrightarrow{\sf{Discount = 16.25}}}

Hence, the discount is Rs.16.25.

\rule{200}2

Now, finding the selling price by substituting the values in the formula :

{\longrightarrow{\sf{Selling \:  Price = Marked \:  Price -  Discount}}}

{\longrightarrow{\sf{Selling \:  Price = 650 - 16.25}}}

{\longrightarrow{\sf{Selling \:  Price =633.75}}}

Hence, the selling price is Rs.633.75.

\rule{300}{2.5}

3 0
2 years ago
What is 3(10x + 7) equal to?
tester [92]
3 (10x+7) is equal to 30x+21
3 0
2 years ago
Read 2 more answers
0.2y + 7 = 24 please help
zzz [600]
First multiply the equation by 5 to get y by itself.
y+35=120
Then subtract 35 from each side to get the integer by itself.
So, final answer:
y=85
8 0
3 years ago
Y=-2(x-3)^2 +10<br> Y=4x
shepuryov [24]

Answer:

i might be wrong but 8 if not (2,8) if not sorry

Step-by-step explanation:

7 0
2 years ago
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