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Tanzania [10]
2 years ago
15

Difference of Squares gives which complex factors for the expression +3?

Mathematics
1 answer:
Oduvanchick [21]2 years ago
3 0

The difference of squares is:

(x+i√3)(x-i√3)

So the correct option is the last one, D.

<h3>Which expression gives x^2 + 3?</h3>

For a complex number:

Z = a + b*i

We define the complex conjugate of Z as:

Z' = a - b*i

Such that the product between the complex number and its complex conjugate gives:

Z*Z' = a^2 + b^2

Now, of you look at option D, you can see we have the product of a number and its conjugate, then we can write the product and use the above rule to get:

(x + i\sqrt{3} )*(x - i\sqrt{3} ) = x^2 + (\sqrt{3} )^2 = x^2 + 3

Which is what we wanted to get, so that is the correct option.

If you want to learn more about complex numbers:

brainly.com/question/10662770

#SPJ1

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<span>Solve for d.
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</span><span>Solve for p.
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           This is equivalent to 2p+9>2p.
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<u>Here are your fill-ins:</u>

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The remainders from synthetic division are 0 each time.

See the attachment for the synthetic division numbers.

_____

The reduced quadratic is ...

... x² -6x +13 = 0

Solving by completing the square, we have ...

... (x -3)² = -4

... x = 3 ± 2i

_____

The quadratic formula would tell you ...

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