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Question 2 of 5

Answer 1

The number of solutions in each equation are as follows:

1. 1 solution: 4^x = 2^{-x}
2. 2 solution: 3/2x + 2 = 2^{x} + 1     and     3x + 1 = 2^{-x}.
3. No solution: 4^x + 2 = 3^x - 1       and     2x - 5 = 3^{x} + 2.

How to determine the number of solutions?

In order to determine the number of solutions, we would split the single equation to two different equations and then plot a graph, so as to reveal their solutions.

This ultimately implies that, the number of solutions is equal to the point of intersection between the lines of the equations plotted on a graph.

In conclusion, the number of solutions in each equation are as follows:

1. 1 solution: 4^x = 2^{-x}
2. 2 solution: 3/2x + 2 = 2^{x} + 1     and     3x + 1 = 2^{-x}.
3. No solution: 4^x + 2 = 3^x - 1       and     2x - 5 = 3^{x} + 2.

Read more on number of solutions here: brainly.com/question/12558210

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