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spayn [35]
3 years ago
7

Solve the compound inequality.

Mathematics
1 answer:
aivan3 [116]3 years ago
5 0

Option D:

x

Solution:

Given compound inequality:

6-x>15 \text { or } 2 x-9 \geq 3

Let us first solve 6-x>15.

Subtract 6 from both sides.

6-x-6>15-6

-x>9

To reverse the inequality multiply by -1  on both sides.

(-x)(-1)

x

Now solve the next inequality 2 x-9 \geq 3.

Add 9 on both sides.

2 x-9+9 \geq 3+9

2 x \geq 12

Divide by 2 on both sides.

$\frac{2 x}{2} \geq \frac{12}{2}

x \geq 6

Combine the inequality.

x

Option D is the correct answer.

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Can someone answer this and please explain it???
gregori [183]
It is D because you would do x+6 and would get y so it represents direct proportion
7 0
3 years ago
Suppose a baker claims that the average bread height is more than 15cm. Several of this customers do not believe him. To persuad
laila [671]

Answer:

17-2.262\frac{1.9}{\sqrt{10}}=15.641    

17+2.262\frac{1.9}{\sqrt{10}}=18.359    

So on this case the 95% confidence interval would be given by (15.641;18.359)    

And since the lower limit for the confidence interval is higher than 15 we can conclude that at 5% of significance the true mean is higher than 15 cm

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=17 represent the sample mean

\mu population mean (variable of interest)

s=1.9 represent the sample standard deviation

n=10 represent the sample size  

Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=10-1=9

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,9)".And we see that t_{\alpha/2}=2.262

Now we have everything in order to replace into formula (1):

17-2.262\frac{1.9}{\sqrt{10}}=15.641    

17+2.262\frac{1.9}{\sqrt{10}}=18.359    

So on this case the 95% confidence interval would be given by (15.641;18.359)    

And since the lower limit for the confidence interval is higher than 15 we can conclude that at 5% of significance the true mean is higher than 15 cm

4 0
3 years ago
For what values of x is the expression below defined?<br> √x+4÷√1-x
wariber [46]

Answer:

x=1

Step-by-step explanation:

4 0
1 year ago
Read 2 more answers
a bag contains 60 marbles, some blue and some green. the ratio of blue marbles to green ones is 1:5. how many blue marbles are t
olga55 [171]
Hello!

For every 1 blue marble there are 5 greens

You add the numbers in the ratio

1 + 5 = 6

Divide this number from the amount of marbles

60 / 6 = 10

Multiply the ratio by this

1 * 10 = 10

5 * 10 = 50

There are 10 blue marbles and 50 green ones

The answer is 10

Hope this helps!
4 0
3 years ago
Find the probability that a data value picked at random from a normally distributed population will have a standard score that c
DerKrebs [107]
P(z < 3)
From the normal distribution table,
P(z < 3) = 0.9987
8 0
3 years ago
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