Question

A 0.340 kg particle moves in an xy plane according to x(t) 15.00 2.00t 4.00t 3 and y(t) 25.00 7.00t 9.00t 2 , with x and y in meters and t in seconds. At t 0.700 s, what are

Answer 1

The displacement of the particle after 0.7 second in x direction is 17.77 m and the displacement in y direction is 34.31 m.

What is displacement?

Displacement is a vector quantity that refers to "how far out of place an object is".

Displacement measures the object's overall change in position.

Displacement of the particle in x direction

x(t) = 15 + 2t + 4t³

where;

• t is time of motion in seconds
• x is displacement, measured in meters

after time, t = 0.7 second

x(0.7) = 15 + 2(0.7) + 4(0.7)³

x(0.7) = 17.77 m

Displacement of the particle in y direction

x(t) = 25 + 7t + 9t²

after time, t = 0.7 second

x(0.7) = 25 + 7(0.7) + 9(0.7)²

x(0.7) = 34.31 m

Thus, the displacement of the particle after 0.7 second in x direction is 17.77 m and the displacement in y direction is 34.31 m.

Learn more about displacement here: brainly.com/question/2109763

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