Question

Instructions: Given the vertex, fill in the vertex form of the quadratic function..

Answer 1

Answer:

$\implies y=(x-2)^2-6$

Step-by-step explanation:

Vertex form of a quadratic equation:

$y=a(x-h)^2+k$

where:

• (h, k) is the vertex
• a is some constant

Given vertex:  (2, -6)

⇒ h = 2 and k = -6

Substitute the values of h and k into the formula:

$\implies y=a(x-2)^2+(-6)$

$\implies y=a(x-2)^2-6$

As we have not been given a value for the constant $a$, assume this is 1.

Therefore, the vertex form of the quadratic function with vertex (2, -6) is:

$y=(x-2)^2-6$

Learn more about vertex form here:

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Answer 2

• (h,k)=(2,-6)

Vertex form

• y=a(x-h)²+k

a=1

Put values

• y=(x-2)²-6