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Simora [160]
2 years ago
12

According to USA Today, the average cost of a private university is $50,000 with a population standard deviation of $2,500. 100

universities are randomly selected and the average income of those 100 universities was $49,450. Using the 5 step hypothesis testing process, can you support the claim that the average cost of private universities are decreasing? Use a .01 significance level. (Use the z or t value of -2.2) What is your conclusion based on p-value?
Mathematics
1 answer:
Colt1911 [192]2 years ago
8 0

Using the z-distribution, it is found that since the p-value is less than 0.05, there is evidence to support the claim that the average cost of private universities are decreasing.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if the average cost is still of $50,000, that is:

H_0: \mu = 50000

At the alternative hypothesis, it is tested if the average cost is decreasing, that is:

H_1: \mu < 50000

<h3>What is the test statistic?</h3>

The test statistic is:

z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}

In which:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • \sigma is the standard deviation of the population.
  • n is the sample size.

The parameters for this problem are:

\overline{x} = 49450, \mu = 50000, \sigma = 2500, n = 100

Hence:

z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{49450 - 50000}{\frac{2500}{\sqrt{100}}}

z = -2.2.

<h3>What is the p-value and the conclusion?</h3>

Using a z-distribution calculator, for a left-tailed test, as we are testing if the mean is less than a value, with z = -2.2, the p-value is of 0.0139.

Since the p-value is less than 0.05, there is evidence to support the claim that the average cost of private universities are decreasing.

More can be learned about the z-distribution at brainly.com/question/16313918

#SPJ1

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