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2 years ago

Can someone please help me with this, i’m a little stuck

Mathematics

1 answer:

Artist 52 [7]2 years ago

7 0

Answer: 420 minutes in 7 hours. 2 minutes in 120 seconds.

Step-by-step explanation: Multiply 7x60, as there are 60 minutes per hour. Divide 120/60 to find how many minutes are within those many seconds.

You might be interested in

For the series 16, 24, 36, 54,... find S7.

diamong [38]

24 - 16 = 8
36 - 24 = 12
54 - 36 = 18

So, obviously, this isn't an arithmetic sequence.

24/16 = 3/2
36/24 = 3/2
54/36 = 3/2

Aha! This is a geometric sequence.

Now, let's find the 7th term in this sequence!

$a_n = a_1 \cdot r^{n-1}$

We're trying to solve for a_7.
We know that a_1 is 16
We know that n = 7
We know that r = 3/2 or 1.5

Plug it in!

$a_n = a_1 \cdot r^{n-1}\\\\a_7 =16 \cdot 1.5^{7-1}\\\\a_7 = 16 \cdot 1.5^6\\\\a_7 = 16 \cdot 11.390625\\\\\boxed{\bf{ a_7 = 182.25}}$

The seventh term is 182.25

5 0

3 years ago

Which of the following errors can be reduced only by increasing the sample size? a. systematic error b. random sampling error c.

garik1379 [7]

Answer:

The correct answer is

b. random sampling error

Step-by-step explanation:

Sampling is a statistical method of selecting a predefined number of observations from a larger population to determine the characteristics of and to represent the larger population.

A sampling error is a type of error in statistics that is as a result of a difference between the calculated statistical values of a selected sample and that of the entire population. A sample of a population with an error does not properly represent the statistics of the population.

By the definition of sampling in statistics, sampling error can be eliminated by Increasing the size of the sample taken from the larger population, analogous central limit theorem.

4 0

3 years ago

Please solve fast. I will give Brainleist or whatever it’s called

alina1380 [7]

Answer:

84in

Step-by-step explanation:

84in

4 0

3 years ago

Power Series Differential equation

KatRina [158]

The next step is to solve the recurrence, but let's back up a bit. You should have found that the ODE in terms of the power series expansion for $y$

$\displaystyle\sum_{n\ge2}\bigg((n-3)(n-2)a_n+(n+3)(n+2)a_{n+3}\bigg)x^{n+1}+2a_2+(6a_0-6a_3)x+(6a_1-12a_4)x^2=0$

which indeed gives the recurrence you found,

$a_{n+3}=-\dfrac{n-3}{n+3}a_n$

but in order to get anywhere with this, you need at least three initial conditions. The constant term tells you that $a_2=0$ , and substituting this into the recurrence, you find that $a_2=a_5=a_8=\cdots=a_{3k-1}=0$ for all $k\ge1$ .

Next, the linear term tells you that $6a_0+6a_3=0$ , or $a_3=a_0$ .

Now, if $a_0$ is the first term in the sequence, then by the recurrence you have

$a_3=a_0$
$a_6=-\dfrac{3-3}{3+3}a_3=0$
$a_9=-\dfrac{6-3}{6+3}a_6=0$

and so on, such that $a_{3k}=0$ for all $k\ge2$ .

Finally, the quadratic term gives $6a_1-12a_4=0$ , or $a_4=\dfrac12a_1$ . Then by the recurrence,

$a_4=\dfrac12a_1$
$a_7=-\dfrac{4-3}{4+3}a_4=\dfrac{(-1)^1}2\dfrac17a_1$
$a_{10}=-\dfrac{7-3}{7+3}a_7=\dfrac{(-1)^2}2\dfrac4{10\times7}a_1$
$a_{13}=-\dfrac{10-3}{10+3}a_{10}=\dfrac{(-1)^3}2\dfrac{7\times4}{13\times10\times7}a_1$

and so on, such that

$a_{3k-2}=\dfrac{a_1}2\displaystyle\prod_{i=1}^{k-2}(-1)^{2i-1}\frac{3i-2}{3i+4}$

for all $k\ge2$ .

Now, the solution was proposed to be

$y=\displaystyle\sum_{n\ge0}a_nx^n$

so the general solution would be

$y=a_0+a_1x+a_2x^2+a_3x^3+a_4x^4+a_5x^5+a_6x^6+\cdots$
$y=a_0(1+x^3)+a_1\left(x+\dfrac12x^4-\dfrac1{14}x^7+\cdots\right)$
$y=a_0(1+x^3)+a_1\displaystyle\left(x+\sum_{n=2}^\infty\left(\prod_{i=1}^{n-2}(-1)^{2i-1}\frac{3i-2}{3i+4}\right)x^{3n-2}\right)$

4 0

3 years ago

I dunno how to do this im just hoping people know the answer

9966 [12]

Answer:

its always wrong

Step-by-step explanation:

any variable always has a holder of 1

so 01b doesnt equal 4

6 0

4 years ago

Read 2 more answers