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Fiesta28 [93]
2 years ago
5

There is a 40% probability that a student PASSES their first statistics exam. Using a Binomial Distribution, if we randomly sele

ct 7 students: What is the probability that more than 5 PASS their first statistics exam
Mathematics
1 answer:
melamori03 [73]2 years ago
4 0

The probability that more than 5 students will pass their exam is 0.0188416.

<h3>How to find the probability?</h3>

The probability that a student passes their examination = 40% = 0.4

The probability that more than 5 students pass their statistics exam = Probability that 6 students pass their exam + Probability that 7 students pass their exam

The probability that 6 students pass their exam =

7C_{6} (0.4)^{6} (0.6)^{1}\\=7(0.4)^6(0.6)\\=0.0172032

The probability that 7 students pass their exam =

7C_{7} (0.4)^{7} (0.6)^{0}\\=(0.4)^7\\=0.0016384

The probability that more than 5 students pass their statistics exam = 0.0172032 + 0.0016384

= 0.0188416

Therefore, we have found the probability that more than 5 students will pass their exam to be 0.0188416.

Learn more about probability here: brainly.com/question/24756209

#SPJ4

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What is the intersection of the following sets? G = {3, 7, 8, 9} H = {2, 5, 7, 8}
weeeeeb [17]

"The intersection (∩) of a pair of sets (G and H) is a third set (I) composed by the elements that belong, at the same time, to both given sets."

According to this definition:

Given the sets:

G = {3, 7, 8, 9}

H = {2, 5, 7, 8}

The Intersection is:

G ∩ H = I = {7, 8}

:-)

5 0
3 years ago
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Will award brainlyist! 15 pts!<br> Find the perimeter of the window to the nearest hundredth.
yawa3891 [41]

Answer:

7.71

Step-by-step explanation:

The diameter is 3, so the arc length is 180/360 * 3pi or 3pi/2. Now you add the 3 in the base, so it is 3pi/2 + 3 or approximately 7.71 (I used a calculator for that).

3 0
3 years ago
A street vendor earns $20 for each day of work plus $4 for
loris [4]

Answer:

(C)

Step-by-step explanation:

20 for each day=20x

4 for hot dogs sold=4x

20x+4x

(C)

4 0
3 years ago
An instructor who taught two sections of engineering probability last term, the first with 20 students and thesecond with 30, de
Oliga [24]

Answer:

0.207

Step-by-step explanation:

This is an hypergeometric distribution problem

An hypergeometric distribution has the same sense as the discrete probabilities of binomial distribution, but unlike binomial distribution, hypergeometric distribution does not allow replacement.

Binomial distribution expresses the probability of picking k objects from n with replacement, but hypergeometric distribution expresses picking k objects from n without replacement, with the finite total population, N, containing K objects.

It is expressed mathematically as

h(k: n, K, N) = (ᴷCₖ)(ᴺ⁻ᴷCₙ₋ₖ)/(ᴺCₙ)

where

k = number of students in the 2nd section required to be in the first 15 graded projects (number of successes) = 10

n = total number of first graded projects (number of trials) = 15

K = number of students in the 2nd section of the class = 30

N = total number of students = 50

h(10: 15, 30, 50) = (³⁰C₁₀)(⁵⁰⁻³⁰C₁₅₋₁₀)/(⁵⁰C₁₅)

h(10: 15, 30, 50) = (³⁰C₁₀)(²⁰C₅)/(⁵⁰C₁₅)

= (30,045,015)(15,504)/(2,250,829,575,120)

P(X = 10) = 0.207

Hope this Helps!!!

7 0
3 years ago
How do you find the point slope form? (given 2 points)
belka [17]

Point-slope form is written as : y - y1 = m(x - x1), where m is the slope and (x1, y1) is the point.

The slope (m) is found by the change in Y over the change in X

Slope = (y2 - y1) / (x2 - x1)

You can use either given point for x1 and y1 so you would calculate the slope and replace m with the slope, then replace x1 and y1 in the equation with their value.

8 0
3 years ago
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