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Alchen [17]
2 years ago
7

The 90% confidence interval for the mean one week amusing time in new york city is 5.22 less than mean less than 5.98 minutes co

nstruct a 95% confidence interval based on the same data which interval provides more information
Mathematics
1 answer:
jasenka [17]2 years ago
8 0

The 95% confidence interval based on the same data is 5.15 < μ < 6.05

Because it has a longer interval, the 95 percent confidence interval offers more details.

<h3>What is a confidence interval?</h3>

The likelihood that a parameter will fall between two values near the mean is shown by a confidence interval.

Confidence intervals quantify how certain or uncertain a sampling technique is.

Confidence intervals are used by statisticians to gauge the degree of uncertainty in a sample variable.

The 90% confidence interval is given by:

Mean - 1.645(S.D./\sqrt{n}) < μ < Mean + 1.645(S.D./\sqrt{n})

2μ = 5.22 + 5.98 = 11.2

μ = 11.2 / 2 = 5.6

Thus,

5.6 - 5.22 = 1.645(S.D./\sqrt{n}) = 0.38

S.D./\sqrt{n} = 0.38 / 1.645 = 0.231

The 95% confidence interval is given by:

Mean - 1.96(S.D./\sqrt{n}) < μ < Mean + 1.96(S.D./\sqrt{n})

=5.6 - 1.96(0.231) < μ < 5.6 + 1.96(0.231)

= 5.6 - 0.4528 < μ < 5.6 + 0.4528

= 5.15 < μ < 6.05

The 95% confidence interval provides more information because it has a larger interval.

Learn more about confidence intervals here:

brainly.com/question/14294413

#SPJ4

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Find the basis for the subspace of R^3 spanned by S = {(81, 63, 12), (27, 21, 4), (9, 7, 1)). {(0, 0, 1), (9, 0, 0), (0, 7, 0);
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Answer with explanation:

A basis of a subspace in R³ is the set of vectors that spans the subspace means the set of vectors, and is linearly  independent.

The meaning of span is if any set of vectors can be written as linear combination of other vector.

For example , {a, b,c}, {p,q,r} and {x,y,z} are three set of vectors.

If ,{a,b,c} can be wriiten as {pm +x n, q m+y n, r m+z n}, then we say that  {a,b,c} spans the set of vectors.

1.

S={(81, 63, 12), (27, 21, 4), (9, 7, 1)}

Writing the set of vectors in matrix form

  \left[\begin{array}{ccc}81&63&12\\27&21&4\\9&7&1\end{array}\right]\\\\R_{2} \Rightarrow 3R_{2}-R_{1}\\\\R_{3} \Rightarrow 9R_{3}-R_{1}\\\\\left[\begin{array}{ccc}81&63&12\\0&0&0\\0&0&0\end{array}\right]

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As all the three vectors are linearly dependent.So, Basis=1.

2.

{(0, 0, 1), (9, 0, 0), (0, 7, 0)}

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So, Basis =3

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{(1, 0, 0), (0, 0, 1), (0, 7, 0)}

All the three vectors are Linearly Independent.

So, Basis=3

4. {(0, 0, 1), (9,7, 0)}

These two vectors can't be written as a linear combination of other.So these two vectors are Independent.So,

Basis=2

5. {9,0,0), (0,7, 0)}

These two vectors can't be written as linear combination of each other.So these two vectors are Independent.So,

Basis=2

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