Answer:
Benedict's test which is meant to detect non-reducing sugar like sucrose from reducing sugars like glucose, fructose or galactose can be used to identify sucrose.
Explanation:
Glucose, fructose and galactose are reducing sugars so they can easily be identified against non-reducing like sucrose. A reducing sugar is a kind of sugar which has a free aldehyde or ketone group. Free aldehyde and ketone groups act as a reducing agent and they are capable of reducing other substances. In this situation, the reducing sugar reduces other substances and themselves get oxidized. In contrast to this, a non-reducing sugar can not act as a reducing agent because it has lack of a free aldehyde or ketone group.
Benedict's test is a test which is used to identify a non reducing sugar from reducing sugars. In this test, a reducing sugar (Glucose, fructose or galactose) is heated with Benedict's solution which leads to the change of color of solution to orange-red/ brick red. But no such color change will be detected if sucrose is heated with Benedict's solution.
The answer is one of the sandy options i think two but i am not completely sure
1.The trait is recessive. This means both your parents were carries, but did not show the trait. For example, B represents the allele, you're parents would have to both be Bb. This means that they are carriers, and you could have inherited either BB/Bb/bb - you actually inherited bb, which means because its a recessive trait you will show the trait.
2. For your children, it depends on who you have them with. Because you're bb, you will definitely pass on the b allele, so any child you have would be a carrier and could potentially have the trait. If you have a child with someone BB, all your offspring will be Bb (carriers- as the kid gets one allele form each parent). If you have a child with someone who is bb, all your kids would definitely have the trait. However, if you have a child with someone who as Bb, then the four outcomes are Bb Bb bb bb, so there would be a 50% chance of your kid having the trait.
Hope this helps!! :)
I think it’s D: X-linked dominant bc there is a dominant allele in the genotype for ones indicated in green. I am not sure about this so plz check other sources too.
By using a punnet square,, all of the grafted branches will be S(sweet)s(sour),, so the offspring will be mutated