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noname [10]
2 years ago
13

given 2,4,3,-1 as input, what is the output for the following program:total_product = 1 user_value = int(input()) while user_val

ue > 0: total_product = total_product * user_value user_value = int(input()) print('Product:', total_product, end='')
Computers and Technology
1 answer:
AlekseyPX2 years ago
8 0

The python program for any of the given values is as written below.

<h3>How to run a Program in Python?</h3>

We are told to use input for the python program as;

2, 4, 3, -1

Now, the python program using 2 as user value and 1 as total product gives us the program as;

total_product = 1

user_value = (input(1)) #while user_value > 0:

total_product = total_product * user_value

user_value = (input(2))

print('Product:2', total_product, end='2')

Read more about Python Program at; brainly.com/question/26497128

#SPJ1

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The three tasks within data harmonization, namely: data consolidation, data cleansing, and data formatting use techniques called
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Data harmonization refers to the process of combining the data of varying files and formats ,name conventions and columns and transforming the same into one data set.

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By adopting the Data harmonization technique we can reduce the problem of redundant data and conflicting standard

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4 years ago
The instruction format of a computer is given by one indirect bit, opcode bits, register address bits, immediate operand bits an
oksian1 [2.3K]

Answer:

Following are the answer to this question:

Explanation:

A)

The memory size is 1 Giga Bytes which is equal to 2^{30}

\texttt{Number of address bits    \ \ \ \ \ \ \ \ \ \ \ \ \ \            Number of addresses}\\\\ \ \ \ \ 30  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \                                 2^{30}= 1073741824

B) \texttt{I \ \ \ Opcode  \ \ \ Register address \ \ \  Immediate operand \ \ \    Memory address}\\\\\\\textt{1 \ bit  \  \ \ \ \ \ 128  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \    2 \ bits   \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \   24 \ bits  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  \ \ \ \ \ \ \ \ \           30 \ bits}\\\\\\            = 2^7 \\\\ = 7 \ bits

calculating the register Bits:

= 64-(1+7+24+30)\\\\=64 -62\ \  bits\\\\= 2\ \ bits\\

C)

Immediate value size while merging the additional benefit with the address field:

= 2^{24} + 2^{30}\\\\= 2^{54}\\\\\texttt{Range before combining(-,+) 24 bits   \ \ \ \ \ \       Range after combining( -,+)54bits}\\\\                         \textt{-2^{12} from + (2^{12}-1)   \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \                                    -2^{27} from + (2^{27}- 1)}

= \frac{24}{2} = 12\\\\= \frac{54}{2} = 27

The range is accomplished by dividing the bits by 2 into the two sides of the o and the number is one short to 0.

8 0
3 years ago
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