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2 years ago

Can someone show me how to do this

Mathematics

1 answer:

lbvjy [14]2 years ago

7 0

Answer:

True

Step-by-step explanation:

We got the formula for that:

F=ma

now if you replace the given data, it's gonna be

F=5 kg×3m/s²====> F=15kg.m/s²

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Simplify each algebraic axpression 4y+6y+5x-2y

Mkey [24]

Answer:

8y+5x

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7 0

1 year ago

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Calculate a vector c in the same direction of the vector a and that has the same length as the vector b

Viktor [21]

For any scalar $t>0$ , $t\vec a$ is a vector pointing in the same direction as $a$ .

To force this vector to have the same length as another vector $\vec b$ , first normalize $t\vec a$ by dividing it by its norm,

$\dfrac{t\vec a}{\|t\vec a\|}=\dfrac{t\vec a}{t\|\vec a\|}=\dfrac{\vec a}{\|\vec a\|}$

then multiply this vector by the norm of $\vec b$ , so that

$\vec c=\dfrac{\|\vec b\|}{\|\vec a\|}\vec a$

To confirm that $\vec c$ has the same length as $\vec b$ :

$\|\vec c\|=\left\|\dfrac{\|\vec b\|}{\|\vec a\|}\vec a\right\|=\dfrac{\|\vec b\|}{\|\vec a\|}\|\vec a\|=\|\vec b\|$

8 0

3 years ago

YOU HAVE BEN CHANGING DIESEL DISPENSERS FOR 35 MINS. YOU HAVE 5 SHOWERS THAT NEED TO BE CLEANED. HOW MANY MINUTES SHOULD IT TAKE

ExtremeBDS [4]

Each would take 7 minutes

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3 years ago

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Compare the theoretical probability to the experimental probability of landing on H.

cestrela7 [59]

The correct statement comparing the theoretical and experimental probabilities is given as follows:

$\frac{1}{4} < \frac{7}{25}$ .

<h3>What is a probability?</h3>

A probability is given by the number of desired outcomes divided by the number of total outcomes.

The theoretical probability is taken before any experiment. Since the four sections are equal, the theoretical probability is:

T(H) = 1/4.

The experimental probability is taken considering previous experiments. Out of 100 tosses, 28 landed on H, hence:

E(H) = 28/100 = 7/25.

Hence the correct statement is:

$\frac{1}{4} < \frac{7}{25}$ .

More can be learned about probabilities at brainly.com/question/14398287

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4 0

1 year ago

I NEED HELP!! please show all work

PtichkaEL [24]

Take the logarithm of both sides. The base of the logarithm doesn't matter.

$4^{5x} = 3^{x-2}$

$\implies \log 4^{5x} = \log 3^{x-2}$

Drop the exponents:

$\implies 5x \log 4 = (x-2) \log 3$

Expand the right side:

$\implies 5x \log 4 = x \log 3 - 2 \log 3$

Move the terms containing x to the left side and factor out x :

$\implies 5x \log 4 - x \log 3 = - 2 \log 3$

$\implies x (5 \log 4 - \log 3) = - 2 \log 3$

Solve for x by dividing boths ides by 5 log(4) - log(3) :

$\implies \boxed{x = -\dfrac{ 2 \log 3 }{ 5 \log 4 - \log 3 }}$

You can stop there, or continue simplifying the solution by using properties of logarithms:

$\implies x = -\dfrac{ \log 3^2 }{ \log 4^5 - \log 3 }$

$\implies x = -\dfrac{ \log 9 }{ \log 1024 - \log 3 }$

$\implies \boxed{x = -\dfrac{ \log 9 }{ \log \frac{1024}3 }}$

You can condense the solution further using the change-of-base identity,

$\implies \boxed{x = -\log_{\frac{1024}3}9}$

5 0

2 years ago