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alex41 [277]
2 years ago
13

Thomas took 3h to paint a room. Brian could paint the same room in 6h. How long would it take for both of them to finish paintin

g the same room together?
please help !! no algebra please​
Mathematics
1 answer:
kaheart [24]2 years ago
7 0

Answer:

2 hours

Step-by-step explanation:

If Thomas can paint 1/3 = 2/6 of the room in a hour and Brian can paint 1/6 of the room in an hour. Which means in an hour they can collectively paint 3/6 = 1/2 of the room. Now you need to find how long it would take then to paint 2/2 of the room. Knowing that 1/2+1/2 = 2/2, it would take them 2 hours to paint the room together

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Worth 25 points!
MrRissso [65]

Answer:

1) \sqrt{-48}=4\sqrt{3} \ i

2) \sqrt{-63}=3\sqrt{7} \ i

3) \sqrt{-72}=6\sqrt{2} \ i

4) \sqrt{-24}=4\sqrt{6} \ i

5) \sqrt{-84}=2\sqrt{21} \ i

6) \sqrt{-99}=3\sqrt{11} \ i

Step-by-step explanation:

We need to simply the following :

<u>Note: For all questions given we know that </u>\sqrt{-1}=i<u> using it in all the given questions.</u>

1) \sqrt{-48}

Factors of 48 are: 2x2x2x2x3

\sqrt{-48}\\=\sqrt{48}\sqrt{-1}  \\=\sqrt{2\times2\times2\times2\times3}\ i\\=  \sqrt{2^2\times2^2\times3}\ i\\=2\times2\sqrt{3} \ i \\=4\sqrt{3} \ i

2) \sqrt{-63}

Factors of 63 are: 3x3x7

\sqrt{-63}\\=\sqrt{63}\sqrt{-1}  \\=\sqrt{3\times3\times7}\ i\\=  \sqrt{3^2\times7}\ i\\=3\sqrt{7} \ i

3) \sqrt{-72}

Factors of 72 are: 2x2x2x3x3

\sqrt{-72}\\=\sqrt{72}\sqrt{-1}  \\=\sqrt{2\times2\times2\times3\times3}\ i\\=  \sqrt{2^2\times3^2\times2}\ i\\=2\times3\sqrt{2} \ i \\=6\sqrt{2} \ i

4) \sqrt{-24}

Factors of 24 are: 2x2x2x3

\sqrt{-24}\\=\sqrt{24}\sqrt{-1}  \\=\sqrt{2\times2\times2\times3}\ i\\=  \sqrt{2^2\times2\times3}\ i\\=2\sqrt{2\times3} \ i \\=2\sqrt{6} \ i

5) \sqrt{-84}

Factors of 84 are: 2x2x3x7

\sqrt{-84}\\=\sqrt{84}\sqrt{-1}  \\=\sqrt{2\times2\times3\times7}\ i\\=  \sqrt{2^2\times3\times7}\ i\\=2\sqrt{21} \ i

6) \sqrt{-99}\\

Prime factors of 99 are: 3x3x11

\sqrt{-99}\\=\sqrt{99}\sqrt{-1}  \\=\sqrt{3\times3\times11}\ i\\=  \sqrt{3^2\times11}\ i\\=3\sqrt{11} \ i \\=3\sqrt{11} \ i

6 0
3 years ago
In the number 6.253
slamgirl [31]

Answer:

place value of 2 is 100

Step-by-step explanation:

please brainleist my answer

4 0
3 years ago
Read 2 more answers
A mechanic’s pay for working 5 in 1 half hours is $96.47. Which calculation can be used to determine the mechanic’s hourly wage,
BARSIC [14]

Answer:

96.47/ 5.5 = hourly wage

3 0
3 years ago
Read 2 more answers
Which of the following will have a negative result A.-8 - (-10) B. 12-14 C.7-(-3)
Lena [83]
B would have a negative result because 12-14 is -2
4 0
3 years ago
Company 1: 3.4 defects per 980,000 occurrences Company 2: 4 defects per 1,115,783 occurrences Company 3: 18 defects per 5,999,52
Gelneren [198K]

Given Information:  

Company 1: defects = 3.4

Company 1: units = 980,000

Company 2: defects = 4

Company 2: units = 1,115,783

Company 3: defects = 18

Company 3: units = 5,999,521

Required Information:  

six-sigma level = ?

Answer:

Company 1: Possible

Company 3: Impossible

Company 3: Possible

Step-by-step explanation:

The six sigma levels are from 1 to 6 where 1 represents lowest quality level and 6 represents highest quality level

To find out sigma level first we have to find out DPU and DMPU

Where DPU is no. of defects divided by no. of units

And DMPU is DPU multiplied by 1 million

Company 1:

DPU = 3.4/980,000 = 0.0000030612

DMPU = 0.0000030612*1,000,000 = 3.06

Company 2:

DPU = 4/1,115,783 = 0.000003584

DMPU = 0.000003584*1,000,000 = 3.58

Company 3:

DPU = 18/5,999,521 = 0.00000300

DMPU = 0.00000300*1,000,000 = 3.0

According to six sigma tables, for six-sigma level, DMPU must be equal or less than 3.4. As you can see only company 1 and 3 has DMPU less than 3.4 therefore, it is possible for company 1 and company 3 to meet six-sigma level but impossible for company 2.

3 0
3 years ago
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